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9476 / 2027
Organic Chemistry

Lesson 19 of 34

A covalently attached halogen must first be released before an ionic halide test

Hydrolysis distinguishes reactivity; silver nitrate identifies the released halide.

A-Level 9476 (2026-2027)

  • I can distinguish organic halogen compounds experimentally.Syllabus

    Syllabus 9476, 11.5(c). Distinguish organic halogen compounds experimentally.

  • I can relate fluoroalkane uses to relative inertness.Syllabus

    Syllabus 9476, 11.5(d). Relate fluoroalkane uses to relative inertness.

  • I can distinguish CFC and replacement environmental effects.Syllabus

    Syllabus 9476, 11.5(e). Distinguish CFC and replacement environmental effects.

A covalently attached halogen must first be released before an ionic halide test

Hydrolysis distinguishes reactivity; silver nitrate identifies the released halide.

Hydrolyse, then test the ions
  1. Warm with aqueous NaOH

    Similar halogenoalkanes release halide ions at different rates, depending on the C-X bond strength and the mechanism. Chlorobenzene does not react under these conditions.

  2. Acidify with dilute HNO3

    This neutralises the excess hydroxide, which would otherwise form silver oxide and confuse the result. Do not use HCl, because it adds chloride.

  3. Add aqueous AgNO3

    Cl- gives a white AgCl precipitate, Br- a cream AgBr precipitate and I- a yellow AgI precipitate. How each behaves with dilute and concentrated ammonia can confirm which halide it is.

Compare hydrolysis rates only when the temperature, solvent, concentrations and carbon chains are the same. For the same chain, RI usually hydrolyses faster than RBr, which is faster than RCl, because the bond strength rises in the opposite order. Testing the organic liquid directly does not work, because the halogen is bonded to carbon, not present as X- ions.

Strong C-F bonds help make many fluoroalkanes and fluorohalogenoalkanes unreactive. That stability made them useful as refrigerants and special fluids, together with suitable physical properties. But because they are so unreactive near the ground, they can last long enough to reach the upper atmosphere.

A replacement can solve one problem while retaining another
FamilyOzone issueOther environmental point
CFCsContain chlorine and can lead to stratospheric ozone destruction after high-energy UV breakdown.Persistent greenhouse gases as well as ozone-depleting substances.
HCFCsContain H as well as Cl; more readily attacked in the lower atmosphere, but still have ozone-depleting potential.Can still contribute significantly to greenhouse warming.
HFCsContain no chlorine, so avoid the chlorine-driven ozone-depletion mechanism.Many are potent greenhouse gases; absence of chlorine does not mean no environmental impact.

The syllabus asks for these environmental differences, not the detailed radical mechanism of ozone depletion by CFCs and HCFCs. Do not treat low reactivity near the ground, harm to ozone and the greenhouse effect as one single property.

Check your understanding

1-chlorobutane, 1-bromobutane and 1-iodobutane are added to separate tubes of warm aqueous ethanolic AgNO3. Which observation is correct?

  1. A white precipitate appears first, because the C-Cl bond is the most polar
  2. The three precipitates appear together, since the skeletons are the same
  3. No precipitate forms, because halogens bonded to carbon do not meet Ag+
  4. A yellow precipitate appears first, because the C-I bond is the weakest
Show the answer

A yellow precipitate appears first, because the C-I bond is the weakest

Water substitutes the halogen and releases X-, which Ag+ precipitates. Breaking C-X is the slow step, and bond energy falls from C-Cl to C-I, so yellow AgI appears first and white AgCl last.

Check your understanding

CFCs were replaced by HFCs. Which statement about this change is correct?

  1. HFCs break down at once in the lower air, so they cause no environmental harm.
  2. HFCs are inert like CFCs, so they reach the stratosphere and release fluorine that destroys ozone.
  3. HFCs have no chlorine, so they do not destroy ozone, but many are strong greenhouse gases.
Show the answer

HFCs have no chlorine, so they do not destroy ozone, but many are strong greenhouse gases.

CFCs are inert, so they reach the stratosphere, where UV breaks C-Cl bonds and the Cl atoms destroy ozone. HFCs avoid this because they contain no chlorine, but many trap heat strongly.