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Organic Chemistry

Topic 16 of 34

The ring and side-chain respond to different conditions

State the catalyst, light condition and temperature before predicting where substitution occurs.

A-Level 9476 (2026-2027)

The ring and side-chain respond to different conditions

State the catalyst, light condition and temperature before predicting where substitution occurs.

Reactions of benzene and methylbenzene
ReactionReagents and conditionsProducts and catalytic role
Ring chlorinationCl2 with anhydrous AlCl3; electrophilic substitution conditions.Benzene → chlorobenzene + HCl. AlCl3 is a Lewis acid catalyst.
Ring brominationBr2 with anhydrous AlBr3.Benzene → bromobenzene + HBr. AlBr3 is a Lewis acid catalyst.
Benzene nitrationConcentrated HNO3 + concentrated H2SO4, maintained at 50 °C.Nitrobenzene + water. H2SO4 acts as a Bronsted-Lowry acid catalyst in generating the electrophile.
Methylbenzene nitrationThe same concentrated-acid mixture, maintained at 30 °C.Mainly 2- and 4-nitromethylbenzene under mononitration conditions.
Friedel-Crafts alkylationHalogenoalkane with anhydrous AlCl3 or AlBr3, as appropriate.Benzene + CH3Cl → methylbenzene + HCl; the Lewis acid activates the halogenoalkane.
Methyl side-chain halogenationCl2 or Br2, UV light at room temperature.C6H5CH3 → C6H5CH2X initially; further substitution can occur.
Complete side-chain oxidationHot alkaline KMnO4 followed by dilute acid, or hot acidified KMnO4.Methylbenzene → benzoic acid. The aromatic ring is retained.

Concentrated sulfuric acid protonates nitric acid, enabling formation of NO2+: HNO3 + H2SO4 ⇌ NO2+ + HSO4- + H2O. Nitration then follows electrophilic substitution and the acid catalyst is regenerated. The syllabus explicitly specifies 30 °C for methylbenzene and 50 °C for benzene; these temperatures are part of these named conditions.

Positions relative to an existing substituent at carbon 1
Existing groupFavoured incoming positionsElectronic point
Alkyl, OH, NH22 and 4 (with position 6 equivalent to 2 in the simple monosubstituted case).Electron donation generally activates the ring and favours ortho/para substitution.
NO2, COOH, CHO, COR, CN3 (with position 5 equivalent).Electron withdrawal generally deactivates the ring and favours meta substitution.
Cl or Br directly on the ring2 and 4.Halogens are the useful distinction: overall deactivating by withdrawal, yet ortho/para directing through lone-pair donation.

Activation describes how fast the ring reacts relative to benzene; direction describes where substitution occurs. They are not the same property. Steric hindrance can reduce substitution next to a bulky group, so do not assume that every allowed position is formed in equal amounts.

Worked example

Same starting compound, different reaction site

Compare methylbenzene with Br2/AlBr3 and with Br2/UV at room temperature.

  1. Lewis-acid conditions generate a strong electrophile for the aromatic pi system.
  2. The methyl group directs ring substitution mainly to positions 2 and 4.
  3. UV conditions initiate a radical chain and favour substitution in the alkyl side-chain.
Answer

Br2/AlBr3 gives mainly 2- and 4-bromomethylbenzene; Br2/UV gives C6H5CH2Br initially. Use structures to avoid confusing a ring bromine with a bromomethyl side-chain.

Ordinary vigorous side-chain oxidation requires a hydrogen on the carbon directly attached to the ring. Methylbenzene satisfies this condition: C6H5CH3 + 3[O] → C6H5COOH + H2O. In alkaline oxidation the carboxylate forms first, so acidification is needed to isolate the carboxylic acid.