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Redox Chemistry

Full chapter

Redox Chemistry

Track electrons through reactions, electrolysis and electricity-producing cells.

O-Level 6092 (2026) / SEC G3 K324 (2027)

01

Recognise oxidation and reduction

Use the model that makes the electron change easiest to see.

Equivalent redox descriptions
ModelOxidationReduction
Oxygen transferGain of oxygenLoss of oxygen
Hydrogen transferLoss of hydrogenGain of hydrogen
Electron transferLoss of electronsGain of electrons
Oxidation stateIncreaseDecrease

Oxidation and reduction happen together: electrons lost by one species are gained by another. In CuO(s) + H2(g) -> Cu(s) + H2O(g), copper(II) oxide loses oxygen and is reduced; hydrogen gains oxygen and is oxidised. During addition of hydrogen to an alkene, the organic compound gains hydrogen and is reduced.

Oxidation state is an accounting number. An uncombined element has state 0. A monatomic ion has its ion charge. In the common compounds here, oxygen is usually -2 and hydrogen +1; exceptions must be supplied or recognised from context. The states sum to zero in a neutral compound or to the overall charge in an ion.

Worked example

Follow electrons and oxidation states

Explain Zn(s) + CuSO4(aq) -> ZnSO4(aq) + Cu(s).

  1. The reacting ions give Zn(s) + Cu2+(aq) -> Zn2+(aq) + Cu(s).
  2. Zn -> Zn2+ + 2e-: oxidation state rises 0 to +2, so zinc is oxidised.
  3. Cu2+ + 2e- -> Cu: state falls +2 to 0, so copper ions are reduced.
Answer

Zinc transfers electrons to copper(II) ions. Sulfate is a spectator.

Check your understandingIs H+ + OH- -> H2O a redox reaction?Think it through, then reveal the answer
No. The oxidation states of hydrogen (+1) and oxygen (-2) remain unchanged. A reaction can occur without electron transfer or oxidation-state change.
02

Identify the agent from what it does

The oxidising agent is itself reduced.

An oxidising agent accepts electrons and causes another species to be oxidised. It is reduced. A reducing agent supplies electrons and is oxidised. In the zinc/copper-ion reaction, Cu2+ is the oxidising agent and Zn is the reducing agent; copper metal is a product, not the agent added at the start.

Test an unknown redox agent
ReagentObservationInference
Aqueous potassium iodideInitially colourless solution becomes brown as iodine formsUnknown oxidises I- to I2; it acts as an oxidising agent
Acidified potassium manganate(VII)Purple solution becomes colourlessUnknown reduces manganate(VII); it acts as a reducing agent

For the iodide test, 2I-(aq) -> I2(aq) + 2e- shows iodide losing electrons. For manganate(VII), use the acidified reagent specified: conditions affect its products and colours. A colour change is an observation; the assignment of oxidising or reducing behaviour is the inference.

Check your understandingAn unknown decolourises acidified potassium manganate(VII). Is the unknown oxidised or reduced?Think it through, then reveal the answer
It is oxidised: it supplies electrons and acts as a reducing agent. The manganate(VII) reagent is reduced.
03Pure only

Electrolysis of a molten compound

A power supply forces chemical change using mobile ions.

Electrolysis passes electric current through a molten or dissolved ionic compound, the electrolyte, causing chemical changes at electrodes. In the solid, ions are fixed in a lattice; once molten or dissolved they can move. This supports the ionic model. Electrons move through metal wires; ions carry charge through the electrolyte.

Molten sodium chloride with inert electrodes
  1. Negative cathode

    Na+ ions move towards it and gain electrons: Na+ + e- -> Na.

  2. Positive anode

    Cl- ions move towards it and lose electrons: 2Cl- -> Cl2 + 2e-.

  3. Products

    Sodium metal and chlorine gas form. At the operating temperature sodium is liquid; chlorine bubbles at the anode.

For a molten binary ionic compound, there are only its constituent cations and anions to discharge. The metal forms at the cathode and the non-metal at the anode, with inert electrodes. For molten lead(II) bromide: Pb2+ + 2e- -> Pb and 2Br- -> Br2 + 2e-. Balance atoms and charge in each half-equation.

Check your understandingWhy does solid sodium chloride fail to undergo the same electrolysis?Think it through, then reveal the answer
Its ions cannot move through the lattice to carry current. Melting frees the ions to move; it does not create the ions from neutral NaCl molecules.
04Pure only

Aqueous electrolysis: more than one possible ion

Water introduces competing products.

In aqueous electrolysis, consider the solute ions and the water. With inert electrodes, a metal less reactive than hydrogen, such as copper, is usually deposited at the cathode. For a very reactive metal ion such as Na+, hydrogen forms instead. At the anode, sulfate is generally not discharged; oxygen forms from water/hydroxide. Halide concentration matters: concentrated chloride favours chlorine, while dilute chloride solution is treated here as giving oxygen.

Apply selective discharge to a new solution
  1. List species and electrode material

    For aqueous potassium iodide with inert electrodes, consider K+, I- and water (H+ and OH-). Molten KI has no water competing.

  2. Choose the cathode product

    Potassium is above hydrogen in the reactivity series. In the school aqueous model, hydrogen forms rather than potassium metal. For a metal below hydrogen, such as copper or silver, the metal is normally deposited.

  3. Choose the anode product

    Halide discharge forms the corresponding halogen: bromide gives bromine; iodide gives iodine. For this iodide solution iodine forms; 2I-(aq) -> I2(aq) + 2e-. Chloride needs the dilute/concentrated comparison shown below. Sulfate is not discharged in these examples: oxygen forms from water/hydroxide.

  4. Check atoms, charge and observations

    The iodide half-equation has two iodine atoms and total charge -2 on each side. The anode region becomes brown as iodine dissolves; hydrogen bubbles at the cathode. Do not describe every halogen product as a gas.

Predict products with inert electrodes
ElectrolyteCathodeAnode
Aqueous copper(II) sulfateCopperOxygen
Dilute aqueous sodium chlorideHydrogenOxygen
Concentrated aqueous sodium chlorideHydrogenChlorine
Useful balanced half-equations
ProcessHalf-equation
Copper depositionCu2+(aq) + 2e- -> Cu(s)
Hydrogen from water2H2O(l) + 2e- -> H2(g) + 2OH-(aq)
Oxygen from hydroxide4OH-(aq) -> O2(g) + 2H2O(l) + 4e-
Chlorine from chloride2Cl-(aq) -> Cl2(g) + 2e-

Worked example

Construct a half-equation from an unfamiliar ion charge

An aqueous solution contains Ag+ ions and silver is discharged at an inert cathode. A separate molten lead(II) bromide cell produces bromine at the anode. Construct the relevant half-equations.

  1. At the cathode an Ag+ ion gains one electron to make a neutral silver atom: Ag+(aq) + e- -> Ag(s).
  2. At the anode bromide ions lose electrons. Bromine is Br2, so begin 2Br- -> Br2, then add 2e- on the right to balance charge.
  3. For the molten-cell anode use Br-(l) and Br2(g); the molten electrolyte is hot enough for bromine to be a gas. Check both atoms and net charge.
Answer

Cathode in the silver solution: Ag+(aq) + e- -> Ag(s). Anode in molten lead(II) bromide: 2Br-(l) -> Br2(g) + 2e-. Each equation must balance atoms and charge.

Worked example

Compare dilute and concentrated brine

Explain why changing NaCl concentration can change one electrode product.

  1. Na+ is not deposited from either aqueous solution; hydrogen forms at the cathode.
  2. In dilute solution, oxygen forms at the inert anode.
  3. At high chloride concentration, chloride is preferentially discharged and chlorine forms.
Answer

Cathode product remains hydrogen; anode product changes. Always state aqueous/molten, concentration and electrode material.

Check your understandingWhat happens to the blue colour during electrolysis of copper(II) sulfate with inert electrodes?Think it through, then reveal the answer
It becomes paler as Cu2+ ions are removed at the cathode and are not replenished by an inert anode. Copper deposits and oxygen is produced.
05Pure only

Make the electrodes part of the design

Copper electrodes behave differently from inert ones.

To purify copper, use impure copper as the anode, pure copper as the cathode, and aqueous copper(II) sulfate as electrolyte. At the anode, Cu(s) -> Cu2+(aq) + 2e-. At the cathode, Cu2+(aq) + 2e- -> Cu(s). Copper transfers from the impure electrode to the pure one; some impurities collect as anode sludge. Detailed industrial operation is not required.

The anode loses mass and the cathode gains mass. Copper ions removed at the cathode are replenished at the copper anode, so concentration remains approximately constant in the simple model. This contrasts with an inert anode, where oxygen forms and the blue solution fades.

For copper electroplating, make the object to be coated the cathode, use copper as the anode, and choose a solution containing Cu2+. Clean the object first so the coating adheres. Electroplating can improve appearance or provide a protective surface; the coating metal and intended use determine the benefit.

Check your understandingA student makes a key the anode when trying to copper-plate it. What should change?Think it through, then reveal the answer
The key must be the cathode so Cu2+ gains electrons and deposits on it. Copper supplies the anode, which dissolves to replenish ions.
06Pure only

Use a reaction to generate electricity

A simple cell converts chemical energy into electrical energy.

A simple cell contains two different electrodes in an electrolyte connected through an external circuit. A more reactive metal tends to lose electrons more readily. In a zinc/copper cell using dilute acid, zinc is oxidised: Zn(s) -> Zn2+(aq) + 2e-. Electrons travel through the wire towards copper, where hydrogen ions can gain them: 2H+(aq) + 2e- -> H2(g). The electrolyte carries ionic current and completes the circuit.

Electron flow in a simple cell

Zinc loses electrons that flow through the external wire to copper; hydrogen ions accept electrons at the copper surface.

Schematic simple cell; electron flow is in the external conductor, not through the solution.

Hydrogen can be obtained from water by electrolysis or from hydrocarbons. In a hydrogen fuel cell it reacts with oxygen to produce water and electricity directly: 2H2(g) + O2(g) -> 2H2O(l). Water is the point-of-use product, but overall environmental impact depends on how the hydrogen and electricity were produced. Detailed fuel-cell construction is not required.

Check your understandingHow does a simple cell differ from electrolysis in energy direction?Think it through, then reveal the answer
A cell uses a spontaneous chemical reaction to supply electrical energy. Electrolysis uses an external electrical supply to drive chemical change. In both, oxidation is electron loss and reduction is electron gain.

Quick revision

Revisit the essentials, then return to an explanation when you need it.

Keep the roles straight
TermMeaning
OxidationElectron loss; oxidation state rises
ReductionElectron gain; oxidation state falls
Oxidising agentAccepts electrons and is reduced
Reducing agentSupplies electrons and is oxidised
Pure only

Pure: list all ions, electrode material and concentration before predicting electrolysis products. At the cathode reduction occurs; at the anode oxidation occurs.

Scope and references

Learning outcomes and sources

7. Redox Chemistry (6092 / K324). Use the outcome map to find the explanation for a particular syllabus requirement.

See the learning outcome map
  1. 7.1(a) Define oxygen/hydrogen redox

    • Oxygen gain/loss
    • Hydrogen loss/gain

    Recognise oxidation and reduction

  2. 7.1(b) Define electron/oxidation-state redox

    • Electron loss/gain
    • Oxidation-state increase/decrease

    Recognise oxidation and reduction

  3. 7.1(c) Identify redox reactions

    • Apply all three descriptive models
    • Distinguish non-redox reactions

    Recognise oxidation and reduction

  4. 7.1(d) Test redox agents

    • KI to brown iodine
    • Acidified KMnO4 purple to colourless

    Identify the agent from what it does

  5. 7.2(a) Explain electrolysis

    • Molten/aqueous ionic electrolytes
    • Chemical changes at electrodes

    Electrolysis of a molten compound

  6. 7.2(b) Use electrolysis as ionic evidence

    • Fixed ions in solids
    • Mobile ions in liquids/solutions

    Electrolysis of a molten compound

  7. 7.2(c) Explain molten NaCl electrolysis

    • Ion movement
    • Sodium and chlorine products
    • Inert electrodes

    Electrolysis of a molten compound

  8. 7.2(d) Predict molten binary products

    • Metal and non-metal products
    • Inert electrodes

    Electrolysis of a molten compound

  9. 7.2(e) Apply selective discharge

    • Cations and reactivity
    • Halides, hydroxide, sulfate
    • Copper sulfate and dilute/concentrated NaCl
    • Inert electrodes

    Aqueous electrolysis: more than one possible ion

  10. 7.2(f) Predict aqueous products

    • Use concentration, ions and electrode information

    Aqueous electrolysis: more than one possible ion

  11. 7.2(g) Construct electrode equations

    • Atoms and charge balanced
    • Relevant state symbols

    Electrolysis of a molten compoundAqueous electrolysis: more than one possible ion

  12. 7.2(h) Explain copper purification

    • Copper sulfate electrolyte
    • Copper electrodes
    • No technical detail required

    Make the electrodes part of the design

  13. 7.2(i) Explain electroplating

    • Copper plating setup
    • A practical use

    Make the electrodes part of the design

  14. 7.2(j) Explain simple cells

    • Two electrodes in electrolyte
    • Reactivity and electron transfer

    Use a reaction to generate electricity

  15. 7.2(k) Describe hydrogen fuel cells

    • Hydrogen from water/hydrocarbons
    • Oxygen reaction generates electricity
    • No construction detail

    Use a reaction to generate electricity