Full chapter
Redox Chemistry
Track electrons through reactions, electrolysis and electricity-producing cells.
O-Level 6092 (2026) / SEC G3 K324 (2027)
Recognise oxidation and reduction
Use the model that makes the electron change easiest to see.
| Model | Oxidation | Reduction |
|---|---|---|
| Oxygen transfer | Gain of oxygen | Loss of oxygen |
| Hydrogen transfer | Loss of hydrogen | Gain of hydrogen |
| Electron transfer | Loss of electrons | Gain of electrons |
| Oxidation state | Increase | Decrease |
Oxidation and reduction happen together: electrons lost by one species are gained by another. In CuO(s) + H2(g) -> Cu(s) + H2O(g), copper(II) oxide loses oxygen and is reduced; hydrogen gains oxygen and is oxidised. During addition of hydrogen to an alkene, the organic compound gains hydrogen and is reduced.
Oxidation state is an accounting number. An uncombined element has state 0. A monatomic ion has its ion charge. In the common compounds here, oxygen is usually -2 and hydrogen +1; exceptions must be supplied or recognised from context. The states sum to zero in a neutral compound or to the overall charge in an ion.
Worked example
Follow electrons and oxidation states
Explain Zn(s) + CuSO4(aq) -> ZnSO4(aq) + Cu(s).
- The reacting ions give Zn(s) + Cu2+(aq) -> Zn2+(aq) + Cu(s).
- Zn -> Zn2+ + 2e-: oxidation state rises 0 to +2, so zinc is oxidised.
- Cu2+ + 2e- -> Cu: state falls +2 to 0, so copper ions are reduced.
Zinc transfers electrons to copper(II) ions. Sulfate is a spectator.
Check your understandingIs H+ + OH- -> H2O a redox reaction?Think it through, then reveal the answer
Identify the agent from what it does
The oxidising agent is itself reduced.
An oxidising agent accepts electrons and causes another species to be oxidised. It is reduced. A reducing agent supplies electrons and is oxidised. In the zinc/copper-ion reaction, Cu2+ is the oxidising agent and Zn is the reducing agent; copper metal is a product, not the agent added at the start.
| Reagent | Observation | Inference |
|---|---|---|
| Aqueous potassium iodide | Initially colourless solution becomes brown as iodine forms | Unknown oxidises I- to I2; it acts as an oxidising agent |
| Acidified potassium manganate(VII) | Purple solution becomes colourless | Unknown reduces manganate(VII); it acts as a reducing agent |
For the iodide test, 2I-(aq) -> I2(aq) + 2e- shows iodide losing electrons. For manganate(VII), use the acidified reagent specified: conditions affect its products and colours. A colour change is an observation; the assignment of oxidising or reducing behaviour is the inference.
Check your understandingAn unknown decolourises acidified potassium manganate(VII). Is the unknown oxidised or reduced?Think it through, then reveal the answer
Electrolysis of a molten compound
A power supply forces chemical change using mobile ions.
Electrolysis passes electric current through a molten or dissolved ionic compound, the electrolyte, causing chemical changes at electrodes. In the solid, ions are fixed in a lattice; once molten or dissolved they can move. This supports the ionic model. Electrons move through metal wires; ions carry charge through the electrolyte.
- Negative cathode
Na+ ions move towards it and gain electrons: Na+ + e- -> Na.
- Positive anode
Cl- ions move towards it and lose electrons: 2Cl- -> Cl2 + 2e-.
- Products
Sodium metal and chlorine gas form. At the operating temperature sodium is liquid; chlorine bubbles at the anode.
For a molten binary ionic compound, there are only its constituent cations and anions to discharge. The metal forms at the cathode and the non-metal at the anode, with inert electrodes. For molten lead(II) bromide: Pb2+ + 2e- -> Pb and 2Br- -> Br2 + 2e-. Balance atoms and charge in each half-equation.
Check your understandingWhy does solid sodium chloride fail to undergo the same electrolysis?Think it through, then reveal the answer
Aqueous electrolysis: more than one possible ion
Water introduces competing products.
In aqueous electrolysis, consider the solute ions and the water. With inert electrodes, a metal less reactive than hydrogen, such as copper, is usually deposited at the cathode. For a very reactive metal ion such as Na+, hydrogen forms instead. At the anode, sulfate is generally not discharged; oxygen forms from water/hydroxide. Halide concentration matters: concentrated chloride favours chlorine, while dilute chloride solution is treated here as giving oxygen.
- List species and electrode material
For aqueous potassium iodide with inert electrodes, consider K+, I- and water (H+ and OH-). Molten KI has no water competing.
- Choose the cathode product
Potassium is above hydrogen in the reactivity series. In the school aqueous model, hydrogen forms rather than potassium metal. For a metal below hydrogen, such as copper or silver, the metal is normally deposited.
- Choose the anode product
Halide discharge forms the corresponding halogen: bromide gives bromine; iodide gives iodine. For this iodide solution iodine forms; 2I-(aq) -> I2(aq) + 2e-. Chloride needs the dilute/concentrated comparison shown below. Sulfate is not discharged in these examples: oxygen forms from water/hydroxide.
- Check atoms, charge and observations
The iodide half-equation has two iodine atoms and total charge -2 on each side. The anode region becomes brown as iodine dissolves; hydrogen bubbles at the cathode. Do not describe every halogen product as a gas.
| Electrolyte | Cathode | Anode |
|---|---|---|
| Aqueous copper(II) sulfate | Copper | Oxygen |
| Dilute aqueous sodium chloride | Hydrogen | Oxygen |
| Concentrated aqueous sodium chloride | Hydrogen | Chlorine |
| Process | Half-equation |
|---|---|
| Copper deposition | Cu2+(aq) + 2e- -> Cu(s) |
| Hydrogen from water | 2H2O(l) + 2e- -> H2(g) + 2OH-(aq) |
| Oxygen from hydroxide | 4OH-(aq) -> O2(g) + 2H2O(l) + 4e- |
| Chlorine from chloride | 2Cl-(aq) -> Cl2(g) + 2e- |
Worked example
Construct a half-equation from an unfamiliar ion charge
An aqueous solution contains Ag+ ions and silver is discharged at an inert cathode. A separate molten lead(II) bromide cell produces bromine at the anode. Construct the relevant half-equations.
- At the cathode an Ag+ ion gains one electron to make a neutral silver atom: Ag+(aq) + e- -> Ag(s).
- At the anode bromide ions lose electrons. Bromine is Br2, so begin 2Br- -> Br2, then add 2e- on the right to balance charge.
- For the molten-cell anode use Br-(l) and Br2(g); the molten electrolyte is hot enough for bromine to be a gas. Check both atoms and net charge.
Cathode in the silver solution: Ag+(aq) + e- -> Ag(s). Anode in molten lead(II) bromide: 2Br-(l) -> Br2(g) + 2e-. Each equation must balance atoms and charge.
Worked example
Compare dilute and concentrated brine
Explain why changing NaCl concentration can change one electrode product.
- Na+ is not deposited from either aqueous solution; hydrogen forms at the cathode.
- In dilute solution, oxygen forms at the inert anode.
- At high chloride concentration, chloride is preferentially discharged and chlorine forms.
Cathode product remains hydrogen; anode product changes. Always state aqueous/molten, concentration and electrode material.
Check your understandingWhat happens to the blue colour during electrolysis of copper(II) sulfate with inert electrodes?Think it through, then reveal the answer
Make the electrodes part of the design
Copper electrodes behave differently from inert ones.
To purify copper, use impure copper as the anode, pure copper as the cathode, and aqueous copper(II) sulfate as electrolyte. At the anode, Cu(s) -> Cu2+(aq) + 2e-. At the cathode, Cu2+(aq) + 2e- -> Cu(s). Copper transfers from the impure electrode to the pure one; some impurities collect as anode sludge. Detailed industrial operation is not required.
The anode loses mass and the cathode gains mass. Copper ions removed at the cathode are replenished at the copper anode, so concentration remains approximately constant in the simple model. This contrasts with an inert anode, where oxygen forms and the blue solution fades.
For copper electroplating, make the object to be coated the cathode, use copper as the anode, and choose a solution containing Cu2+. Clean the object first so the coating adheres. Electroplating can improve appearance or provide a protective surface; the coating metal and intended use determine the benefit.
Check your understandingA student makes a key the anode when trying to copper-plate it. What should change?Think it through, then reveal the answer
Use a reaction to generate electricity
A simple cell converts chemical energy into electrical energy.
A simple cell contains two different electrodes in an electrolyte connected through an external circuit. A more reactive metal tends to lose electrons more readily. In a zinc/copper cell using dilute acid, zinc is oxidised: Zn(s) -> Zn2+(aq) + 2e-. Electrons travel through the wire towards copper, where hydrogen ions can gain them: 2H+(aq) + 2e- -> H2(g). The electrolyte carries ionic current and completes the circuit.
Electron flow in a simple cell
Zinc loses electrons that flow through the external wire to copper; hydrogen ions accept electrons at the copper surface.
Hydrogen can be obtained from water by electrolysis or from hydrocarbons. In a hydrogen fuel cell it reacts with oxygen to produce water and electricity directly: 2H2(g) + O2(g) -> 2H2O(l). Water is the point-of-use product, but overall environmental impact depends on how the hydrogen and electricity were produced. Detailed fuel-cell construction is not required.
Check your understandingHow does a simple cell differ from electrolysis in energy direction?Think it through, then reveal the answer
Quick revision
Revisit the essentials, then return to an explanation when you need it.
| Term | Meaning |
|---|---|
| Oxidation | Electron loss; oxidation state rises |
| Reduction | Electron gain; oxidation state falls |
| Oxidising agent | Accepts electrons and is reduced |
| Reducing agent | Supplies electrons and is oxidised |
Pure: list all ions, electrode material and concentration before predicting electrolysis products. At the cathode reduction occurs; at the anode oxidation occurs.
Scope and references
Learning outcomes and sources
7. Redox Chemistry (6092 / K324). Use the outcome map to find the explanation for a particular syllabus requirement.
See the learning outcome map
7.1(a) Define oxygen/hydrogen redox
- Oxygen gain/loss
- Hydrogen loss/gain
7.1(b) Define electron/oxidation-state redox
- Electron loss/gain
- Oxidation-state increase/decrease
7.1(c) Identify redox reactions
- Apply all three descriptive models
- Distinguish non-redox reactions
7.1(d) Test redox agents
- KI to brown iodine
- Acidified KMnO4 purple to colourless
7.2(a) Explain electrolysis
- Molten/aqueous ionic electrolytes
- Chemical changes at electrodes
7.2(b) Use electrolysis as ionic evidence
- Fixed ions in solids
- Mobile ions in liquids/solutions
7.2(c) Explain molten NaCl electrolysis
- Ion movement
- Sodium and chlorine products
- Inert electrodes
7.2(d) Predict molten binary products
- Metal and non-metal products
- Inert electrodes
7.2(e) Apply selective discharge
- Cations and reactivity
- Halides, hydroxide, sulfate
- Copper sulfate and dilute/concentrated NaCl
- Inert electrodes
7.2(f) Predict aqueous products
- Use concentration, ions and electrode information
7.2(g) Construct electrode equations
- Atoms and charge balanced
- Relevant state symbols
Electrolysis of a molten compoundAqueous electrolysis: more than one possible ion
7.2(h) Explain copper purification
- Copper sulfate electrolyte
- Copper electrodes
- No technical detail required
7.2(i) Explain electroplating
- Copper plating setup
- A practical use
7.2(j) Explain simple cells
- Two electrodes in electrolyte
- Reactivity and electron transfer
7.2(k) Describe hydrogen fuel cells
- Hydrogen from water/hydrocarbons
- Oxygen reaction generates electricity
- No construction detail
- 2026 Pure Chemistry 6092
Official topic 7, pages 16-17. Original explanations mapped to the stated outcomes; 2026 and 2027 topic content agrees.
- 2027 Pure Chemistry K324
Official topic 7, pages 16-17. Original explanations mapped to the stated outcomes; 2026 and 2027 topic content agrees.
- 2026 Combined Chemistry 5086 / 5088
Official topic 7, pages 32. Original explanations mapped to the stated outcomes; 2026 and 2027 topic content agrees.
- 2027 Combined Chemistry K326 / K328
Official topic 7, pages 32. Original explanations mapped to the stated outcomes; 2026 and 2027 topic content agrees.
- Grail: 6092 Chemistry Complete Notes, Version 1
Background consultation: Chapter 13, electrolysis and selective discharge, pp. 55-56. Teaching additions and examples are original; syllabus scope and chemistry independently checked.