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Acid-Base Chemistry

Full chapter

Acid-Base Chemistry

Use ions and reaction patterns to explain acids, bases and salts.

O-Level 6092 (2026) / SEC G3 K324 (2027)

01

Acids, alkalis and pH

Read acidity as an ion balance, not just a colour.

An acid produces H+ ions in aqueous solution. An alkali is a soluble base that produces OH- ions in water. A base neutralises an acid; insoluble copper(II) oxide is a base but is not an alkali. Acidic and alkaline solutions both contain H+ and OH-; their relative concentrations differ.

Universal Indicator and the pH scale
Solution at room temperatureRelative ionspH and typical indicator colour
AcidicMore H+ than OH-Below 7; red through orange/yellow as pH increases
NeutralEqual H+ and OH-7; green
AlkalineMore OH- than H+Above 7; blue through purple

Compare colours with the supplied indicator chart. Universal Indicator estimates a pH range; a suitable calibrated pH probe gives a numerical reading. We use qualitative comparisons here, not calculations of pH from hydrogen-ion concentration.

Soil pH affects nutrient availability and plant growth. Calcium hydroxide can treat excessively acidic soil because it neutralises acid. Adding too much creates a different problem: overly alkaline soil. Determine the starting pH and add an appropriate amount rather than assuming more is better.

Check your understandingDoes a neutral solution contain no H+ ions?Think it through, then reveal the answer
No. It has equal concentrations of H+ and OH-. Neutrality concerns their balance, not the absence of ions.
02

Recognise the reaction pattern

Predict the salt and the other products.

Acid and base reactions
ReactantsProductsBalanced example
Acid + suitable metalSalt + hydrogenMg(s) + 2HCl(aq) -> MgCl2(aq) + H2(g)
Acid + baseSalt + waterCuO(s) + H2SO4(aq) -> CuSO4(aq) + H2O(l)
Acid + carbonateSalt + water + carbon dioxideCaCO3(s) + 2HCl(aq) -> CaCl2(aq) + H2O(l) + CO2(g)
Alkali + ammonium salt, warmSalt + water + ammoniaNH4Cl(aq) + NaOH(aq) -> NaCl(aq) + H2O(l) + NH3(g)

The acid supplies the salt anion: hydrochloric acid gives chlorides, sulfuric acid sulfates, and nitric acid nitrates. The metal or base supplies the cation. Not every metal reacts with dilute acid: copper, for example, does not release hydrogen from dilute hydrochloric acid.

For an acid reacting with an alkali, the reacting ions are H+(aq) + OH-(aq) -> H2O(l). This is neutralisation. The other dissolved ions are spectators. For an ammonium salt and alkali, NH4+(aq) + OH-(aq) -> NH3(g) + H2O(l); warming helps ammonia escape.

Worked example

Predict and confirm the gas

Dilute acid is added to a carbonate and bubbles appear. How should the result be described?

  1. Predict carbon dioxide from the carbonate reaction pattern.
  2. Report effervescence as the observation.
  3. Pass the gas into limewater: a white precipitate supports carbon dioxide.
Answer

Effervescence alone does not identify a gas. Carbon dioxide turns limewater milky; hydrogen instead gives a pop with a lighted splint.

Check your understandingWhat salt forms when zinc reacts with dilute sulfuric acid?Think it through, then reveal the answer
Zinc sulfate, ZnSO4. The complete reaction is Zn(s) + H2SO4(aq) -> ZnSO4(aq) + H2(g).
03

Classify an oxide by its reactions

Metal/non-metal character suggests a pattern, but exceptions matter.

Four oxide classes
ClassBehaviourExamples
BasicReacts with acids to form salt and waterCuO, MgO: generally metal oxides
AcidicReacts with bases to form salt and waterCO2, SO2: generally non-metal oxides
AmphotericReacts with both acids and strong alkalisAl2O3, ZnO
NeutralDoes not show typical acidic or basic oxide reactionsCO, NO; being a non-metal oxide does not guarantee acidity

For example, CO2(g) + 2NaOH(aq) -> Na2CO3(aq) + H2O(l) with excess alkali shows acidic-oxide behaviour. CuO reacting with an acid shows basic behaviour. An insoluble oxide can still be acidic or basic: classification is not determined by whether it dissolves in water.

Check your understandingAn oxide reacts with hydrochloric acid and also with aqueous sodium hydroxide. How is it classified?Think it through, then reveal the answer
Amphoteric. Both reactions are needed to distinguish it from an oxide that is only basic or only acidic.
04Pure only

Strong and weak is different from concentrated and dilute

Separate extent of ionisation from amount per unit volume.

A strong acid ionises essentially completely in water: HCl(aq) -> H+(aq) + Cl-(aq). A weak acid ionises only partly: CH3COOH(aq) reversibly forms H+(aq) and CH3COO-(aq). Many acid molecules remain un-ionised.

Concentration describes the amount of acid per unit volume, whether or not its molecules ionise. A strong acid can be dilute, and a weak acid can be concentrated. At the same concentration, comparing suitable monoprotic acids under the same conditions, the stronger acid produces more H+, usually gives a lower pH and reacts faster initially with magnesium.

Check your understandingDoes diluting hydrochloric acid turn it into a weak acid?Think it through, then reveal the answer
No. It reduces concentration, but hydrochloric acid is still classified as strong because the dissolved acid ionises essentially completely. Strength and concentration answer different questions.
05Pure only

Use solubility rules to choose starting materials

An insoluble product can be separated as a precipitate.

General salt-solubility rules
FamilyRule and important exceptions
Group 1 and ammonium saltsSoluble
NitratesSoluble
ChloridesGenerally soluble; silver chloride and lead(II) chloride are exceptions
SulfatesGenerally soluble; barium sulfate and lead(II) sulfate are insoluble; calcium sulfate is sparingly soluble
CarbonatesGenerally insoluble except Group 1 and ammonium carbonates
HydroxidesGenerally insoluble except Group 1 hydroxides; calcium hydroxide is slightly soluble

Precipitation occurs when dissolved ions meet and form an insoluble solid. Mixing Ba(NO3)2(aq) and Na2SO4(aq) gives BaSO4(s). The ionic equation is Ba2+(aq) + SO42-(aq) -> BaSO4(s). Choose soluble starting salts so both required ions are available to mix.

Check your understandingWhy mix barium nitrate solution with sodium sulfate solution rather than simply mixing the dry solids?Think it through, then reveal the answer
Dissolved Ba2+ and SO4 2- ions can move and meet to form insoluble barium sulfate. Dry ionic solids do not provide freely mixing ions; using solutions makes precipitation effective.
06Pure only

Prepare and purify the salt you want

The method follows the solubility of both product and reactants.

Choose the route
  1. Insoluble salt

    Mix two suitable soluble salts. Filter the precipitate, wash with distilled water, then dry.

  2. Soluble salt with an insoluble reactant

    React dilute acid with excess suitable metal, insoluble base or insoluble carbonate. Filter away excess solid, concentrate the filtrate, cool to crystallise, filter and dry.

  3. Soluble salt from acid and alkali

    Use titration to find exact reacting volumes. Repeat those volumes without indicator, then concentrate and crystallise.

Worked example

Prepare copper(II) sulfate crystals

Choose reagents and explain the key steps.

  1. Warm dilute sulfuric acid gently and add copper(II) oxide in small portions with stirring until some remains unreacted.
  2. Excess solid ensures the acid is used up. Filter away the unreacted oxide.
  3. Gently evaporate some water from the filtrate, then allow it to cool and crystallise.
  4. Filter crystals, wash with a little cold distilled water and dry between filter papers.
Answer

CuO(s) + H2SO4(aq) -> CuSO4(aq) + H2O(l). Copper metal is unsuitable with dilute sulfuric acid because it does not release hydrogen.

A suitable metal such as magnesium can prepare a soluble salt with dilute acid, but extremely reactive metals such as sodium are unsuitable. An insoluble carbonate such as zinc carbonate is another route; effervescence helps track acid consumption. For sodium chloride, both hydrochloric acid and sodium hydroxide remain dissolved, so excess cannot be removed by filtration: titration is needed.

Worked example

Make a soluble salt when both reactants are solutions

Prepare pure potassium chloride crystals from dilute hydrochloric acid and potassium hydroxide solution. Why is titration needed?

  1. Use a pipette to put a known fixed volume of KOH(aq) in a conical flask. Add a few drops of a suitable indicator such as methyl orange.
  2. Add HCl(aq) from a burette while swirling, dropwise near the endpoint. Record initial and final readings to find the volume giving the indicator colour change. Repeat to obtain consistent volumes.
  3. Mix the same measured neutralising volumes in clean apparatus without indicator. KOH(aq) + HCl(aq) -> KCl(aq) + H2O(l).
  4. Gently evaporate some water, cool to crystallise, then filter the crystals, wash with a little cold distilled water and dry.
Answer

Titration avoids soluble excess acid or alkali, which filtration cannot remove. The indicator-free repeat prevents indicator contaminating the salt.

Check your understandingWhy repeat the measured acid and alkali volumes without indicator when preparing a pure salt?Think it through, then reveal the answer
The first titration finds the neutralising volumes. Repeating them without indicator avoids contaminating the salt with indicator; adding arbitrary excess alkali would also leave a soluble impurity.
07Pure only

Ammonia: choose useful industrial conditions

Reversible reactions require a balance between yield, speed and cost.

In the Haber process, nitrogen from air reacts with hydrogen to form ammonia: N2(g) + 3H2(g) reversibly forms 2NH3(g). The syllabus connects hydrogen supply to cracking crude-oil hydrocarbons. The reverse reaction breaks ammonia down, so conversion is not necessarily complete.

Industrial plants use elevated pressure, a moderately high temperature and an iron catalyst. Ammonia is cooled and removed; unreacted nitrogen and hydrogen are recycled. A catalyst speeds attainment of the final composition without improving the equilibrium yield. This chapter uses supplied trends, not Le Chatelier's principle.

Illustrative process data at fixed pressure
TemperatureAmmonia yieldTime to approach final composition
LowerHigherLong
IntermediateIntermediatePractical
HigherLowerShort

Worked example

Interpret a compromise

Given these trends, why might a manufacturer avoid the lowest temperature?

  1. A high eventual yield is not useful if formation is too slow.
  2. An intermediate temperature can give more ammonia per hour despite a lower final percentage.
  3. Higher pressure may improve yield in supplied data but adds compression costs and demands stronger equipment.
Answer

Use yield, production rate and cost together. Do not infer that the highest yield automatically gives the most economical operating conditions.

Check your understandingWhy recycle the gases remaining after ammonia is removed?Think it through, then reveal the answer
Because the reversible reaction leaves unreacted nitrogen and hydrogen. Recycling gives further opportunities to react and reduces raw-material waste.

Quick revision

Revisit the essentials, then return to an explanation when you need it.

Acids supply H+; alkalis supply OH-. Acid + base gives salt and water; carbonate also gives CO2; suitable metal gives H2. Alkali and ammonium salt release NH3 on warming.

Pure only

Pure: select salt preparation from solubility, separate acid strength from concentration, and interpret Haber conditions using supplied yield/rate/cost evidence.

Scope and references

Learning outcomes and sources

5. Acid-Base Chemistry (6092 / K324). Use the outcome map to find the explanation for a particular syllabus requirement.

See the learning outcome map
  1. 5.1(a) Define acids and alkalis

    • Aqueous H+ and OH-
    • Universal Indicator

    Acids, alkalis and pH

  2. 5.1(b) Compare acidity and alkalinity

    • Relative ion concentrations
    • Indicator colours
    • pH scale, no logarithmic calculation

    Acids, alkalis and pH

  3. 5.1(c) Distinguish strong and weak acids

    • Extent of ionisation
    • Distinguish concentration

    Strong and weak is different from concentrated and dilute

  4. 5.1(d) Describe acid reaction patterns

    • Metals, bases and carbonates
    • Salt products

    Recognise the reaction pattern

  5. 5.1(e) Explain neutralisation

    • H+ + OH- -> water

    Recognise the reaction pattern

  6. 5.1(f) Explain control of soil acidity

    • Importance of soil pH
    • Calcium hydroxide treatment

    Acids, alkalis and pH

  7. 5.1(g) Describe base reactions

    • With acids
    • With ammonium salts on warming

    Recognise the reaction pattern

  8. 5.1(h) Classify oxides

    • Acidic, basic, amphoteric, neutral
    • Metal/non-metal character and exceptions

    Classify an oxide by its reactions

  9. 5.2(a) Prepare, separate and purify salts

    • Precipitation
    • Titration
    • Acids with metals, insoluble bases and insoluble carbonates

    Prepare and purify the salt you want

  10. 5.2(b) Apply salt-solubility rules

    • Nitrates
    • Chlorides including silver and lead
    • Sulfates including barium, calcium and lead
    • Carbonates and hydroxides
    • Group 1 and ammonium salts

    Use solubility rules to choose starting materials

  11. 5.2(c) Select a salt-preparation route

    • Suitable starting materials
    • Product and reactant solubility

    Use solubility rules to choose starting materialsPrepare and purify the salt you want

  12. 5.3(a) Identify ammonia feedstocks

    • Nitrogen from air
    • Hydrogen from cracking crude-oil hydrocarbons

    Ammonia: choose useful industrial conditions

  13. 5.3(b) Recognize reversibility

    • Ammonia synthesis and decomposition

    Ammonia: choose useful industrial conditions

  14. 5.3(c) Interpret industrial process data

    • Haber temperature, pressure, rate/yield/cost
    • No Le Chatelier requirement

    Ammonia: choose useful industrial conditions