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The Periodic Table

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The Periodic Table

Explain trends from electrons and structure, then predict the oxides, chlorides and redox behaviour of unfamiliar elements.

A-Level 9476 (2026-2027)

01

A period fills a shell; a group preserves an outer pattern

Outer configurations explain recurring chemistry, but subshell and structure changes interrupt simple trends.

Period 3: sodium to chlorine
ElementOuter configurationTypical highest oxidation number in the specified compounds
Na3s1+1
Mg3s2+2
Al3s23p1+3
Si3s23p2+4
P3s23p3+5
S3s23p4+6
Cl3s23p5Seven outer electrons; chlorine oxides are outside the specified oxide list

Across this period the inner [Ne] core stays the same while nuclear charge increases and electrons enter the third shell. Down Group 2 from Mg to Ba, the outer configuration remains ns2. Down Group 17 from Cl to I, it remains ns2np5. The value of n increases down each group, so the outer electrons occupy more distant shells.

Use these patterns to predict typical ions: Group 2 loses two electrons to give M2+; Group 17 gains one to give X-. This does not mean that every compound consists of ions. Period-3 non-metals also share electrons in covalent compounds.

03

Melting-point patterns reveal changes of structure

The sharp fall after silicon is a change from a giant network to molecular substances.

Period-3 elemental structures
ElementsStructure and melting explanationElectrical behaviour
Na, Mg, AlMetallic. Across these examples, greater positive-ion charge density and more delocalised electrons generally strengthen metallic bonding. Mg and Al have similar melting temperatures; crystal details also matter.Conduct as solids and liquids through mobile electrons.
SiGiant covalent network; melting requires extensive disruption of strong covalent bonds, giving a very high melting point.Semiconductor; conductivity is much lower than an ordinary metal and depends strongly on temperature and impurities.
White P4, S8, Cl2Simple molecular forms. Melting separates molecules against intermolecular attractions, not the covalent bonds inside them.Poor conductors because they lack mobile charged particles.

Among the specified molecular forms, S8 has a larger, more polarizable electron cloud than P4 or Cl2 and generally stronger instantaneous dipole-induced dipole attractions. Hence its melting point is higher. State the allotrope: red or black phosphorus cannot be explained by pretending it consists of white-phosphorus P4 molecules.

Down Group 17: chlorine, bromine, iodine
  1. Electron clouds become larger

    Cl2 → Br2 → I2 contains progressively more electrons and more readily distorted clouds.

  2. Intermolecular attractions strengthen

    Instantaneous dipoles induce larger dipoles in neighbouring molecules.

  3. Boiling points increase and volatility decreases

    At room conditions chlorine is a gas, bromine a liquid and iodine a solid.

04

Highest oxides progress from ionic bases to covalent acids

Use oxygen at -2 to check the oxidation numbers before explaining the trend.

All six specified highest oxides
OxideElement oxidation number and structureReaction with water
Na2ONa +1; ionic lattice.Na2O + H2O → 2NaOH; strongly alkaline solution.
MgOMg +2; ionic lattice.MgO + H2O → Mg(OH)2, slowly; sparing dissolution gives a weakly alkaline solution.
Al2O3Al +3; predominantly ionic extended solid with appreciable covalent character.No reaction with water under ordinary conditions.
SiO2Si +4; giant covalent network.No reaction with water under ordinary conditions.
P4O10P +5; covalent oxide, commonly represented using P4O10 molecular units.P4O10 + 6H2O → 4H3PO4; acidic solution.
SO3S +6; covalent oxide; molecular description is useful for its vapour.SO3 + H2O → H2SO4; vigorous hydration gives acid.

The highest positive oxidation numbers in these oxides rise with the number of valence electrons available for bonding. These are formal oxidation numbers, not necessarily actual ionic charges: SiO2 is not a lattice of bare Si4+ and O2- ions.

Across the period, increasing element electronegativity reduces the electronegativity difference from oxygen. Bonding changes from predominantly ionic towards covalent. Oxygen in an ionic basic oxide can accept protons; covalent non-metal oxides instead commonly form oxoacids or react with bases. Silicon dioxide remains insoluble because its extended network is difficult to disrupt, despite being classified as acidic.

Check your understandingWhy is phosphorus +5 in P4O10 rather than +10?Think it through, then reveal the answer
Ten oxygens contribute -20 in total. Four phosphorus atoms must contribute +20, so each phosphorus is +5. The formula subscripts are not themselves oxidation numbers.
05

Amphoteric aluminium compounds react on both sides

The trend is basic -> amphoteric -> acidic; water solubility is a separate question.

Acid-base reactions of the oxides
TypeExamplesRepresentative balanced reaction
BasicNa2O and MgOMgO(s) + 2H+(aq) → Mg2+(aq) + H2O(l)
Amphoteric: with acidAl2O3Al2O3(s) + 6H+(aq) → 2Al3+(aq) + 3H2O(l)
Amphoteric: with aqueous NaOHAl2O3Al2O3(s) + 2OH-(aq) + 3H2O(l) → 2[Al(OH)4]-(aq)
AcidicSiO2SiO2(s) + 2OH-(aq) → SiO32-(aq) + H2O(l), with hot concentrated alkali
AcidicP4O10P4O10 + 12OH- → 4PO43- + 6H2O, for complete neutralisation
AcidicSO3SO3 + 2OH- → SO42- + H2O

NaOH is a soluble strong base. Mg(OH)2 is basic but sparingly soluble: limited solubility should not be confused with partial dissociation of the small amount that dissolves. Both react with acids. Al(OH)3 is amphoteric and can dissolve in either acid or excess aqueous sodium hydroxide.

A white aluminium hydroxide precipitate can dissolve two ways
  1. Add acid

    Al(OH)3(s) + 3H+(aq) → Al3+(aq) + 3H2O(l).

  2. Add excess aqueous NaOH

    Al(OH)3(s) + OH-(aq) → [Al(OH)4]-(aq).

  3. Name the evidence

    Dissolution in both acid and alkali supports amphoteric behaviour; the sodium ions are spectators in the second equation.

The familiar acidic classification of SiO2 refers to its reaction with bases, not to dissolution in water. Likewise, no observable reaction with dilute hydrochloric acid is not evidence that a solid is neutral. Distinguish solubility, speed of reaction and acid-base character.

Worked example

Check atoms and charge in an amphoteric equation

Why does Al2O3 + 2OH- → 2[Al(OH)4]- need water?

  1. The products contain eight O atoms and eight H atoms.
  2. Al2O3 plus 2OH- supplies five O and two H.
  3. Add three H2O to the left: this supplies the missing three O and six H. Total charge remains -2 on each side.
Answer

Al2O3 + 2OH- + 3H2O → 2[Al(OH)4]-.

06

Dissolving a chloride is not always the same as hydrolysing it

Compare ionic salts, hydrated metal ions and reactive molecular chlorides.

The five specified chlorides
Chloride and highest oxidation numberBonding or structureBehaviour with excess water
NaCl: Na +1Ionic solid.Dissolves to Na+ and Cl-; approximately neutral solution.
MgCl2: Mg +2Ionic solid.Dissolves to hydrated ions; weak acidity can arise from limited hydrolysis of hydrated Mg2+.
AlCl3: Al +3Substantial covalent character; Al2Cl6 occurs in dry liquid/vapour descriptions.Forms strongly polarising hydrated Al3+ ions; their hydrolysis makes the solution acidic.
SiCl4: Si +4Simple molecular covalent liquid.Hydrolyses to silica (often hydrated) and HCl; acidic solution and white material.
PCl5: P +5Molecular in the gas phase; solid has [PCl4]+ and [PCl6]- ions.Hydrolyses to H3PO4 and HCl in excess water.

The general ionic-to-covalent trend follows decreasing electronegativity difference between the period-3 element and chlorine. AlCl3 requires special care: the small, highly charged aluminium centre strongly polarises the chloride electron cloud, giving substantial covalent character. A simple electronegativity threshold is not a complete explanation.

When AlCl3 enters excess water, aluminium becomes hydrated. The highly charged central ion withdraws electron density from the O-H bonds of coordinated water, allowing proton release: [Al(H2O)6]3+ + H2O ⇌ [Al(H2O)5(OH)]2+ + H3O+. Chloride is not the source of the proton. Do not assume that dissolution automatically precipitates all aluminium as Al(OH)3.

Molecular chloride hydrolysis: amount of water matters
ConditionsBalanced overall reaction
SiCl4 in excess water; hydration of silica simplifiedSiCl4 + 2H2O → SiO2 + 4HCl
PCl5 with limited waterPCl5 + H2O → POCl3 + 2HCl
PCl5 in excess waterPCl5 + 4H2O → H3PO4 + 5HCl

In SiCl4 and PCl5, chlorine attracts the bonding electrons, leaving an electron-poor central atom. Water can donate an oxygen lone pair to that centre; replacement of chlorine by oxygen-containing groups and proton transfer release HCl. This is chemical change of the chloride, whereas dissolving NaCl separates existing ions. Mg2+ has lower charge density than Al3+, so it weakens coordinated O-H bonds less strongly and its hydrated ion releases protons less readily.

Low boiling temperature or volatility supports a discrete molecular structure, whereas high melting temperature and molten conduction support an ionic lattice. Water reactions provide different evidence: vigorous hydrolysis of a molecular chloride does not mean it was an ionic salt before water was added. Name the state when discussing PCl5 or AlCl3.

Worked example

Deduce structure before trying to name a compound

Oxide A has a high melting temperature, does not conduct when solid or molten, does not react with water, and reacts with hot concentrated alkali. Chloride B is a volatile liquid, does not conduct electricity when pure, and reacts vigorously with water to give an acidic solution. What structures do the observations support?

  1. For A, the high melting temperature suggests strong bonding throughout an extended solid. Lack of molten conduction argues against a simple ionic lattice: melting an ionic solid would free its ions to move.
  2. A giant covalent network fits the combined physical evidence. Reaction with alkali establishes acidic oxide behaviour; its failure to react with water does not make it a neutral oxide.
  3. For B, volatility suggests discrete molecules held together by relatively weak intermolecular attractions. Its pure liquid has no mobile ions, consistent with a simple molecular covalent structure.
  4. The acidic solution from B shows hydrolysis. The ions formed in water do not establish that the original liquid was ionic.
Answer

A is consistent with a giant covalent acidic oxide such as SiO2; B with a simple molecular chloride such as SiCl4. These observations support structure classes; naming a unique element would require the permitted element range or additional composition data.

07

Read reduction potentials in their written direction

Group 2 metals reduce other species; halogens oxidise them.

For M2+(aq) + 2e- ⇌ M(s), a more negative standard reduction potential means the metal is more readily oxidised in a suitable paired reaction. Group 2 metals are reducing agents because they lose electrons. The standard potentials become generally more negative from Mg towards Ba, supporting greater reducing power down the group.

For X2 + 2e- ⇌ 2X-(aq), a more positive standard reduction potential means the halogen is a stronger oxidising agent. The usual values are approximately +1.36 V for chlorine, +1.07 V for bromine and +0.54 V for iodine, with the standard physical states specified in the data. Oxidising strength therefore decreases Cl2 > Br2 > I2.

Worked example

Predict a displacement using E degrees

Use +1.36 V for Cl2/Cl- and +1.07 V for Br2/Br- to assess Cl2 + 2Br- → 2Cl- + Br2.

  1. Chlorine is reduced; bromide is oxidised.
  2. Ecell = E(reduction at cathode) - E(reduction for the reverse oxidation pair) = 1.36 - 1.07.
  3. Ecell = +0.29 V, so the written reaction is thermodynamically favourable under standard conditions.
Answer

Chlorine can oxidise bromide to bromine. Reversing the reaction gives -0.29 V and is not favourable under those standard conditions.

08

Two thermal trends need two different explanations

Carbonates depend on cation polarisation; hydrogen halides depend on their covalent bond strength.

Group 2 carbonates decompose on heating: MCO3(s) → MO(s) + CO2(g). Down Mg to Ba, the cation radius increases while its charge remains +2. Charge density and polarising power decrease. The larger cation distorts the large carbonate ion less, so the carbonate is harder to decompose and its thermal stability increases.

A complete carbonate explanation
  1. Same charge, larger cation down the group

    Mg2+ is smaller than Ba2+, so Mg2+ has greater charge density.

  2. Polarise the large anion

    The smaller cation distorts the carbonate electron cloud more strongly, destabilising the carbonate relative to decomposition products.

  3. Predict the heating result

    Magnesium carbonate decomposes more readily; barium carbonate requires stronger heating.

For hydrogen halides, the relevant reaction is 2HX(g) ⇌ H2(g) + X2(g). From HCl to HBr to HI, the halogen atom becomes larger, the H-X bond becomes longer and the bond energy decreases. Thermal stability therefore decreases in that order: HI decomposes most readily.

Choose the mechanism that matches the substance
Trend down the groupKey reasoningDirection of stability
MgCO3 to BaCO3Lower cation charge density and less polarisation of carbonate.Increases
HCl to HILonger, weaker H-X covalent bond.Decreases
Check your understandingIodine is less volatile than chlorine, but HI is less thermally stable than HCl. Is that a contradiction?Think it through, then reveal the answer
No. Volatility concerns intermolecular attractions between X2 molecules. Thermal decomposition of HX concerns breaking H-X covalent bonds. They are different changes involving different interactions.
09

Combine the clues before assigning an element

An inference is strongest when configuration, physical properties and reactions agree.

Worked example

Identify a period-3 element

A period-3 element conducts electricity. Its hydroxide precipitate dissolves in both acid and excess aqueous NaOH. Its chloride gives an acidic solution. Which element is most consistent?

  1. Electrical conduction favours one of the metals, rather than a molecular non-metal.
  2. Amphoteric hydroxide behaviour identifies aluminium among the period-3 metals.
  3. Acidity from hydrolysis of hydrated Al3+ is consistent with the chloride clue.
Answer

Aluminium. The given period matters: amphoteric behaviour alone would not uniquely identify an element across the entire table.

Worked example

Predict a Group-2 comparison

How should strontium compare with magnesium in ionic radius, first ionisation energy and carbonate thermal stability?

  1. Sr2+ has more occupied shells, so its ionic radius is larger.
  2. Greater shielding and distance generally lower the first ionisation energy of Sr.
  3. The larger Sr2+ ion has lower charge density and polarises carbonate less strongly.
Answer

Larger ion, lower first ionisation energy, more thermally stable carbonate. Each prediction uses the mechanism appropriate to that property.

When practical evidence is supplied, distinguish observation from interpretation. "A white precipitate dissolves in excess alkali" is an observation; "the hydroxide is amphoteric" is an interpretation. Use the stated temperature, physical state and reagent excess. If two identities fit, name the additional evidence needed instead of forcing a unique answer.

Quick revision

Revisit the essentials, then return to an explanation when you need it.

Five trends, five explanations
ObservationReason
Atomic radius falls across Period 3.Nuclear charge rises with similar inner shielding.
Melting point falls sharply after Si.Giant covalent network changes to discrete molecules.
Oxides change basic → amphoteric → acidic.Bonding and proton-accepting behaviour change across the period.
Group 2 carbonates become more stable down the group.Larger cations polarise carbonate less.
Hydrogen halides become less stable down Group 17.H-X bonds become longer and weaker.

Remember the exceptions and conditions: Mg/Al and P/S ionisation-energy dips; the ionic-radius jump between cation and anion series; white-phosphorus P4; AlCl3 covalent character; phase-dependent PCl5; partial hydrated-ion hydrolysis rather than automatic hydroxide precipitation.

Scope and references

Learning outcomes and sources

5. The Periodic Table. Use the outcome map to find the explanation for a particular syllabus requirement.

See the learning outcome map
  1. 5(a) Recognise electronic-configuration patterns.

    • Period 3 Na-Cl
    • Group 2 Mg-Ba
    • Group 17 Cl-I

    A period fills a shell; a group preserves an outer pattern

  2. 5(b) Explain atomic and ionic size, first IE and electronegativity trends.

    • (i) Across a period: shielding and nuclear charge
    • (ii) Down a group: shell number, shielding and nuclear charge
    • Subshell/pairing variations and isoelectronic ions

    Compare attraction, shielding and shell number together

  3. 5(c) Interpret melting and conductivity across the period.

    • Metallic elements
    • Giant molecular silicon
    • Simple molecular phosphorus, sulfur and chlorine

    Melting-point patterns reveal changes of structure

  4. 5(d) Explain halogen volatility.

    • Cl2, Br2, I2
    • Instantaneous dipole-induced dipole attraction
    • Polarizability, not X-X bond breaking

    Melting-point patterns reveal changes of structure

  5. 5(e) Explain the specified oxide and chloride patterns.

    • (i) Highest oxidation numbers: Na2O, MgO, Al2O3, SiO2, P4O10, SO3; NaCl, MgCl2, AlCl3, SiCl4, PCl5
    • (ii) Electronegativity and bonding, with AlCl3 treated separately
    • (iii) Water reactions of all six oxides
    • (iv) Acid/base behaviour of all six oxides and NaOH, Mg(OH)2, Al(OH)3; amphoteric reactions with acids and NaOH
    • (v) Water reactions of all five chlorides
    • (vi) Infer oxide/chloride structure from physical and chemical observations

    Highest oxides progress from ionic bases to covalent acidsAmphoteric aluminium compounds react on both sidesDissolving a chloride is not always the same as hydrolysing it

  6. 5(f) Use standard potentials to compare reactivity.

    • (i) Group 2 reducing agents
    • (ii) Group 17 oxidising agents
    • Written half-reaction direction and standard conditions

    Read reduction potentials in their written direction

  7. 5(g) Explain thermal-stability trends.

    • (i) Group 2 carbonates: cation charge density and anion polarizability
    • (ii) Group 17 hydrides: covalent bond energies

    Two thermal trends need two different explanations

  8. 5(h) Predict properties from group membership.

    • Transfer known periodic mechanisms to another member of a specified group

    Combine the clues before assigning an element

  9. 5(i) Infer periodic position and identity from evidence.

    • Physical and chemical properties
    • Nature and likely position
    • Check whether the evidence establishes a unique identity

    Combine the clues before assigning an element