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The Periodic Table

Topic 5 of 6

Group 2 and Group 17 chemistry

Use electrode potentials and explain thermal stability.

A-Level 9476 (2026-2027)

Read reduction potentials in their written direction

Group 2 metals reduce other species; halogens oxidise them.

For M2+(aq) + 2e- ⇌ M(s), a more negative standard reduction potential means the metal is more readily oxidised in a suitable paired reaction. Group 2 metals are reducing agents because they lose electrons. The standard potentials become generally more negative from Mg towards Ba, supporting greater reducing power down the group.

For X2 + 2e- ⇌ 2X-(aq), a more positive standard reduction potential means the halogen is a stronger oxidising agent. The usual values are approximately +1.36 V for chlorine, +1.07 V for bromine and +0.54 V for iodine, with the standard physical states specified in the data. Oxidising strength therefore decreases Cl2 > Br2 > I2.

Worked example

Predict a displacement using E degrees

Use +1.36 V for Cl2/Cl- and +1.07 V for Br2/Br- to assess Cl2 + 2Br- → 2Cl- + Br2.

  1. Chlorine is reduced; bromide is oxidised.
  2. Ecell = E(reduction at cathode) - E(reduction for the reverse oxidation pair) = 1.36 - 1.07.
  3. Ecell = +0.29 V, so the written reaction is thermodynamically favourable under standard conditions.
Answer

Chlorine can oxidise bromide to bromine. Reversing the reaction gives -0.29 V and is not favourable under those standard conditions.

Two thermal trends need two different explanations

Carbonates depend on cation polarisation; hydrogen halides depend on their covalent bond strength.

Group 2 carbonates decompose on heating: MCO3(s) → MO(s) + CO2(g). Down Mg to Ba, the cation radius increases while its charge remains +2. Charge density and polarising power decrease. The larger cation distorts the large carbonate ion less, so the carbonate is harder to decompose and its thermal stability increases.

A complete carbonate explanation
  1. Same charge, larger cation down the group

    Mg2+ is smaller than Ba2+, so Mg2+ has greater charge density.

  2. Polarise the large anion

    The smaller cation distorts the carbonate electron cloud more strongly, destabilising the carbonate relative to decomposition products.

  3. Predict the heating result

    Magnesium carbonate decomposes more readily; barium carbonate requires stronger heating.

For hydrogen halides, the relevant reaction is 2HX(g) ⇌ H2(g) + X2(g). From HCl to HBr to HI, the halogen atom becomes larger, the H-X bond becomes longer and the bond energy decreases. Thermal stability therefore decreases in that order: HI decomposes most readily.

Choose the mechanism that matches the substance
Trend down the groupKey reasoningDirection of stability
MgCO3 to BaCO3Lower cation charge density and less polarisation of carbonate.Increases
HCl to HILonger, weaker H-X covalent bond.Decreases
Check your understandingIodine is less volatile than chlorine, but HI is less thermally stable than HCl. Is that a contradiction?Think it through, then reveal the answer
No. Volatility concerns intermolecular attractions between X2 molecules. Thermal decomposition of HX concerns breaking H-X covalent bonds. They are different changes involving different interactions.