9478 / 2027
Energy and Fields overview

Chapter revision

Revision summary

Key ideas, equations and common mistakes. Open any topic below for the full explanation.

Name the system, force, displacement and interval. Conditions determine which equation can be used and which energy changes belong in the account.

Energy accounts

Total energy change = transfers in - transfers out for a fixed collection of matter. Kinetic, gravitational, electric, elastic, chemical and internal stores are distinct from transfer processes. Work is a transfer; power is a rate.

Count a transfer and its resulting store increase once. Dissipated energy remains in the total account, even when it is less useful for the intended task. Kinetic-plus-potential energy need not stay constant when internal energy increases.

Work and kinetic energy

W = Fs cos θ
Ek = ½mv2
Wnet = ΔEk

For constant force, θ is between force and displacement. Work is positive along motion, negative against it and zero for a perpendicular force. For a varying force component, use signed force-component/displacement area.

Derive kinetic energy with Wnet = Fresultants = mas and v2 - u2 = 2as for straight-line constant acceleration. The derivation assumes constant mass and no relevant rotational/internal change. Squared speed makes kinetic energy a scalar; reversing velocity need not change it.

Fields and force direction

Gravitational field
g = gravitational force / mass, in N/kg. Force on a positive mass is along g. Uniform lines are parallel; radial lines point inward towards a spherical mass.
Electric field
E = force / positive test charge, in N/C. F = qE: positive charge along E, negative charge opposite E. Uniform plate lines run positive to negative; radial lines point away from positive and towards negative point charges.

Field-line tangents give direction; spacing represents strength under a consistent convention. Lines do not cross where the field is defined. They are not compulsory trajectories. A smaller test body's smaller force need not mean a smaller field.

H2 equipotentials: potential is constant along an equipotential surface. A nonzero static field is perpendicular to it. Movement of a fixed mass or charge along it gives zero field work, even though the field force is nonzero. Uniform fields have equipotential planes; radial fields have concentric spherical surfaces.

Field work and potential energy

Wfield = -ΔEp

Apply this to the static gravitational/electric field's work. Positive field work decreases potential energy; negative field work increases it. Use the charge's actual force direction. Work by an external agent equals +ΔEp only when kinetic energy is unchanged and there are no other energy transfers.

Gravitational and electric potential energy depend on interactions and relative positions; elastic potential energy depends on deformation. Changes are independent of a common shift in the energy reference.

Elastic graph area

For slow, reversible loading with negligible kinetic change and dissipation, elastic-energy increase equals stretching-force/extension area. A linear spring through the unloaded origin gives ½kx2. Between nonzero extensions, subtract energies or find only the intervening area.

Trapezia are exact for supplied straight segments and estimates for sampled smooth curves. Convert extension to metres for an area in N m = J. Loading work alone does not prove that all energy can be recovered.

Power and efficiency

Paverage = ΔE/Δt
P = Fv cos θ
Efficiency = useful energy output / total energy input

Mechanical power refers to the named force; θ is its angle to velocity. A zero resultant and constant speed do not imply zero input power. The useful/input power ratio gives efficiency when both rates refer to the same interval.

1 W = 1 J/s, while 1 kWh = 3.6 × 106 J. Equal energies transferred in half the time mean twice the powers, not twice the energies.

For a lift, match load force, vertical rise, time and measured input energy to the same interval. Check whether kinetic energy changes. A label rating or force × speed does not measure the actual electrical input energy.

Quantity and unit reference
QuantityUsual symbolsUnits
Workw, WJ = N m
EnergyE, U, WJ = kg m2 s-2; also kWh
Kinetic; potential energyEk; EpJ
PowerPW = J/s
Gravitational field strengthgN/kg
Electric field strengthEN/C; also V/m
ChargeQ; defined test charge qC; microC = 10-6 C
Force constant; extensionk; xN/m; m
Gravitational; electric potentialφ; VJ/kg; V = J/C

Read symbols in context. W can label work or energy in J, weight in N, or the unit watt when it follows a power value. E can label energy in J or electric field in N/C. Here s or x denotes displacement in m and v denotes velocity in m/s. Efficiency is a ratio with no unit.

Back to energy accounts

Practise exam questions

Write your answer first, then tick the mark points it makes.

Exam-style question

Define work done by a force. A constant resultant force F acts on a body of mass m, initially at rest, and moves it a distance s in the direction of the force. Show that its kinetic energy is then (1/2)mv2, where v is its speed. [4]

Saved on this browser only. Anyone using this browser can see it.

Exam-style question

A car travels at a constant speed of 30 m s-1 on a level road against a total resistive force of 900 N. Its engine is 30% efficient. Calculate the useful power output and the rate at which the engine uses energy from the fuel. [3]

Saved on this browser only. Anyone using this browser can see it.

Exam-style question

A graph of tension F against extension x for a spring is a straight line from the origin to (0.040 m, 12 N). Explain why the area under the graph gives the elastic potential energy stored, and calculate it. [3]

Saved on this browser only. Anyone using this browser can see it.

Exam-style question

Data-based question: A pumped-storage power station [20]

A pumped-storage power station stores energy by pumping water from a lower reservoir to an upper one at night, when electricity is cheap, and lets it flow back down through turbines during the day, when electricity is expensive. The station sends its output to a city along a high-voltage transmission line.

Table 1. Station data
usable volume of upper reservoir1.8 x 106 m3
average height of water above the turbines320 m
volume flow rate through turbines when generating50 m3 s-1
efficiency of turbines and generators90%
efficiency of pumps85%
price paid for electricity at night8 cents per kW h
price received for electricity by day20 cents per kW h
total resistance of transmission line8.0 Ω
density of water1000 kg m-3
  1. (a) Show that the gravitational potential energy of the full upper reservoir, relative to the turbines, is about 5.7 x 1012 J. [2]
  2. (b) Calculate the electrical power output when generating. [3]
  3. (c) Calculate how long the station can generate before the upper reservoir is empty, and check that this is consistent with (a) and (b). [2]
  4. (d) Calculate the electrical energy needed at night to pump the water back up, and the overall efficiency of one full cycle. [3]
  5. (e) Use the prices in Table 1 to evaluate whether one full cycle makes money, even though energy is lost. [3]
  6. (f) The output is transmitted at 400 kV. Calculate the current in the line and the power lost in it. [3]
  7. (g) Calculate the power lost if the same output were transmitted at 132 kV, and explain why the loss is so much larger. [2]
  8. (h) In (a), g was taken as constant at 9.81 N kg-1 over the 320 m height. Explain why this is reasonable. [1]
  9. (i) State one other assumption you made in (b) or (c). [1]

Saved on this browser only. Anyone using this browser can see it.

Quick recall

Card 1 of 5. Answer in your head, then check.

A 2.0 kg crate moves 3.0 m right. An 8.0 N pull acts 60 degrees above the displacement and a constant 2.0 N resistance acts left. Weight and support are perpendicular to the displacement. What is the change in the crate's kinetic energy?

Review a topic

Read whole chapter

Next chapter: Projectile Motion