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Energy and Fields overview

Chapter revision

Revision summary

Key ideas, equations and common mistakes. Open any topic below for the full explanation.

Name the system, force, displacement and interval. Conditions determine which equation can be used and which energy changes belong in the account.

Energy accounts

Total energy change = transfers in - transfers out for a fixed collection of matter. Kinetic, gravitational, electric, elastic, chemical and internal stores are distinct from transfer processes. Work is a transfer; power is a rate.

Count a transfer and its resulting store increase once. Dissipated energy remains in the total account, even when it is less useful for the intended task. Kinetic-plus-potential energy need not stay constant when internal energy increases.

Work and kinetic energy

W = Fs cos θ
Ek = ½mv2
Wnet = ΔEk

For constant force, θ is between force and displacement. Work is positive along motion, negative against it and zero for a perpendicular force. For a varying force component, use signed force-component/displacement area.

Derive kinetic energy with Wnet = Fresultants = mas and v2 - u2 = 2as for straight-line constant acceleration. The derivation assumes constant mass and no relevant rotational/internal change. Squared speed makes kinetic energy a scalar; reversing velocity need not change it.

Fields and force direction

Gravitational field
g = gravitational force / mass, in N/kg. Force on a positive mass is along g. Uniform lines are parallel; radial lines point inward towards a spherical mass.
Electric field
E = force / positive test charge, in N/C. F = qE: positive charge along E, negative charge opposite E. Uniform plate lines run positive to negative; radial lines point away from positive and towards negative point charges.

Field-line tangents give direction; spacing represents strength under a consistent convention. Lines do not cross where the field is defined. They are not compulsory trajectories. A smaller test body's smaller force need not mean a smaller field.

Field work and potential energy

Wfield = -ΔEp

Apply this to the static gravitational/electric field's work. Positive field work decreases potential energy; negative field work increases it. Use the charge's actual force direction. Work by an external agent equals +ΔEp only when kinetic energy is unchanged and there are no other energy transfers.

Gravitational and electric potential energy depend on interactions and relative positions; elastic potential energy depends on deformation. Changes are independent of a common shift in the energy reference.

Elastic graph area

For slow, reversible loading with negligible kinetic change and dissipation, elastic-energy increase equals stretching-force/extension area. A linear spring through the unloaded origin gives ½kx2. Between nonzero extensions, subtract energies or find only the intervening area.

Trapezia are exact for supplied straight segments and estimates for sampled smooth curves. Convert extension to metres for an area in N m = J. Loading work alone does not prove that all energy can be recovered.

Power and efficiency

Paverage = ΔE/Δt
P = Fv cos θ
Efficiency = useful energy output / total energy input

Mechanical power refers to the named force; θ is its angle to velocity. A zero resultant and constant speed do not imply zero input power. The useful/input power ratio gives efficiency when both rates refer to the same interval.

1 W = 1 J/s, while 1 kWh = 3.6 × 106 J. Equal energies transferred in half the time mean twice the powers, not twice the energies.

For a lift, match load force, vertical rise, time and measured input energy to the same interval. Check whether kinetic energy changes. A label rating or force × speed does not measure the actual electrical input energy.

Quantity and unit reference
QuantityUsual symbolsUnits
Workw, WJ = N m
EnergyE, U, WJ = kg m2 s-2; also kWh
Kinetic; potential energyEk; EpJ
PowerPW = J/s
Gravitational field strengthgN/kg
Electric field strengthEN/C; also V/m
ChargeQ; defined test charge qC; microC = 10-6 C
Force constant; extensionk; xN/m; m

Read symbols in context. W can label work or energy in J, weight in N, or the unit watt when it follows a power value. E can label energy in J or electric field in N/C. Here s or x denotes displacement in m and v denotes velocity in m/s. Efficiency is a ratio with no unit.

Back to energy accounts

Practise exam questions

Write your answer first, then tick the mark points it makes.

Exam-style question

Define work done by a force. A constant resultant force F acts on a body of mass m, initially at rest, and moves it a distance s in the direction of the force. Show that its kinetic energy is then (1/2)mv2, where v is its speed. [4]

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Exam-style question

A car travels at a constant speed of 30 m s-1 on a level road against a total resistive force of 900 N. Its engine is 30% efficient. Calculate the useful power output and the rate at which the engine uses energy from the fuel. [3]

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Exam-style question

A graph of tension F against extension x for a spring is a straight line from the origin to (0.040 m, 12 N). Explain why the area under the graph gives the elastic potential energy stored, and calculate it. [3]

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Exam-style question

Data-based question: The range of an electric car [17]

The range of an electric car depends on how fast it is driven. Engineers measured the total resistive force F on a car of mass 1500 kg driven at constant speed v on a level road with no wind. Part of F is rolling resistance from the tyres, which is about 180 N at every speed; the rest is air resistance. The car's battery stores 60 kW h of usable energy, and 85% of the energy taken from the battery does work at the wheels.

Table 1. Resistive force at different speeds
v / m s-11015202530
F / N2804055808051080
  1. (a) The data fit F = 180 + kv2. Use the data at 10 m s-1 to find k, and check it at 20 m s-1. [2]
  2. (b) Calculate the power needed at the wheels at a constant 25 m s-1. [2]
  3. (c) Calculate the power taken from the battery at this speed. [1]
  4. (d) Calculate the range of the car at a constant 25 m s-1. [3]
  5. (e) Calculate the range at a constant 15 m s-1. [2]
  6. (f) A driver says: "If I drive twice as fast, my range halves." Use the data to evaluate this statement. [3]
  7. (g) The car climbs a hill that rises 1 m for every 20 m along the road, at a constant 25 m s-1. Calculate the power needed at the wheels. [3]
  8. (h) State one assumption you made in (d). [1]

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Quick recall

Card 1 of 4. Answer in your head, then check.

A 2.0 kg crate moves 3.0 m right. An 8.0 N pull acts 60 degrees above the displacement and a constant 2.0 N resistance acts left. Weight and support are perpendicular to the displacement. What is the change in the crate's kinetic energy?

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