9477 / 2027

Lesson 4 of 5 / Photosynthesis and energy capture

Fix, reduce and regenerate carbon

Why do most triose phosphates stay in the Calvin cycle?

In this lesson: Explain the three phases of the C3 Calvin cycle and ATP/NADPH use.

About 8 min

The key ideaRubisco fixes CO2; ATP and reduced NADP support reduction; most carbon regenerates RuBP so fixation can continue.

Explore the idea

Keep the carbon acceptor available

3 RuBP (5C) + 3 CO2Fixation by rubisco6 PGA (3C each)ATP + reduced NADPReduction6 TP (3C each)5 TP recycledNet output: 1 TP3 carbons leaveRegeneration uses more ATPTotal: 9 ATP + 6 NADPH

3 CO2 bring 3 new carbons into the cycle. The 5 recycled triose phosphates contain 15 carbons, enough to regenerate 3 five-carbon RuBP. Only 1 triose phosphate is the net output.

TP = triose phosphate; PGA = glycerate 3-phosphate; NADPH = reduced NADP. Reduction uses 6 ATP and 6 NADPH; regeneration uses another 3 ATP. Two net TP can contribute to a six-carbon sugar; glucose is not released directly at every fixation event.

Explanation

In carbon fixation, rubisco catalyses addition of CO2 to five-carbon ribulose bisphosphate, RuBP. The unstable six-carbon product splits into two three-carbon molecules of glycerate 3-phosphate, also called 3-phosphoglycerate or PGA. This is why the pathway is described as C3.

In the reduction phase, ATP supplies energy and reduced NADP supplies reducing power to convert PGA into triose phosphate. ADP, phosphate and oxidised NADP return to support the light-dependent reactions. The cycle does not obtain its energy simply by absorbing a photon directly at rubisco.

For three CO2 fixed, three RuBP produce six PGA and then six triose phosphates. One triose phosphate is a net carbon output; the other five, containing fifteen carbons, regenerate three five-carbon RuBP using additional ATP. This regeneration keeps the carbon acceptor available.

The net production of one three-carbon triose phosphate requires nine ATP and six reduced NADP in the standard accounting. Two net triose phosphates can contribute to a six-carbon sugar. Light-independent means no direct photon step, not independence from the light reactions: ATP and reduced NADP are continually required.

Step by step
  1. 1

    Balance the carbons

    Three CO2 plus fifteen RuBP carbons give eighteen in intermediates.

  2. 2

    Separate output from recycling

    Only three carbons leave per three CO2 in the net model.

  3. 3

    Account for energy

    Nine ATP and six NADPH support one net triose phosphate.

Worked example

Work through the evidence

How many CO2, ATP and reduced NADP are needed for two net triose phosphates in this model?

One way to explain it

Six CO2, eighteen ATP and twelve reduced NADP.

Why this answer works
  • Double the three-CO2 accounting.
  • Most intermediate carbon is recycled into RuBP, not exported each turn.
Is this true? "All six triose phosphates leave after three CO2 are fixed."

Five are needed to regenerate three RuBP; only one is net output in that accounting.

Try a question

What is the direct role of rubisco?
You can return to this lesson any time.