9477 / 2027

Lesson 5 of 7 / Inheritance and genetic problems

Linkage changes gamete probabilities

What do excess parental classes tell you about two loci?

I can explain linkage, crossing-over and altered dihybrid/test-cross ratios.

  • I can solve dihybrid problems involving dominance, codominance, multiple alleles, sex linkage, autosomal linkage and epistasis.Syllabus

    Syllabus 9477, Core 2(x). Solve dihybrid problems involving dominance, codominance, multiple alleles, sex linkage, autosomal linkage and epistasis.

  • I can solve test-cross problems.Syllabus

    Syllabus 9477, Core 2(y). Solve test-cross problems.

  • I can explain linkage, crossing-over and altered dihybrid ratios.Syllabus

    Syllabus 9477, Core 2(z). Explain linkage, crossing-over and altered dihybrid ratios.

About 8 min

Make a guess. You are not marked.

Two genes are on the same chromosome. Are their alleles always inherited together?

  1. No. They assort independently, like any genes.
  2. No. Crossing-over can separate them.
  3. Yes. Linked genes can never be separated.
Show the answer

No. Crossing-over can separate them.

Crossing-over between the loci produces recombinant gametes. The further apart the loci, the more often it happens.

The key idea

Linked alleles are often transmitted together; crossing-over creates recombinant gametes whose frequency can be estimated from an informative test cross.

Build from gametes

How does recombination change gamete frequencies?

Parental arrangement: AB / ab. The tester produces only ab gametes.

One pair of homologuesABabAB45%ab45%Ab5%aB5%Total recombinant fraction: 10%

Ab and aB are recombinant classes, each 5%. AB and ab are parental classes, each 45%. At 50%, the frequencies resemble independent assortment; this alone does not prove the genes are on different chromosomes.

Write the cross in chromosome-line notation

Parental phenotypesdominant for bothxrecessive for bothParental genotypesxABabababGametes (circled)ABparental45%abparental45%Abrecombinant5%aBrecombinant5%xaballOffspring genotypesABabababAbabaBabOffspring phenotypesA and Bparental45%a and bparental45%A and brecombinant5%a and Brecombinant5%Recombinant frequency = 10%

Capital letters in a phenotype mean the dominant feature is shown. Alleles written above the double line are on one homologue, and alleles below are on the other.

Bar lengths represent expected proportions, not an observed sample. The equal reciprocal classes assume a simple cross with equal viability. Recombination frequency between two loci does not exceed 50% in this model; multiple crossovers can conceal some exchange events.

Explanation

Linked genes are on the same chromosome, so in a genetic diagram you must show which alleles share a chromosome. Use chromosome-line notation: write the alleles on one homologue above a pair of parallel lines and the alleles on the other homologue below them. A and B above the lines with a and b below shows that A and B are on one chromosome. Some school mark schemes deduct a mark for the slash shorthand AB/ab inside a genetic diagram, so keep the slash for sentences only. AB/ab and Ab/aB are different arrangements even though both individuals are AaBb. Without crossing-over between the loci, only the two parental combinations are produced.

Label the gametes and offspring as parental or recombinant. Parental gametes carry the same combination of alleles as a chromosome of the parent: AB and ab from A B over a b. Recombinant gametes carry a new combination, Ab or aB, made by crossing-over. In a test cross the parental offspring classes are the most frequent, and the two recombinant classes are smaller and roughly equal.

A crossover between non-sister homologous chromatids between the loci can create recombinant Ab and aB chromatids from AB/ab. Only chromatids involved in that crossover are recombinant. More distant loci are more likely to have a crossover between them, but multiple crossovers limit a simple distance interpretation.

In a test cross with ab/ab, offspring classes reveal the heterozygote's gametes. If counts are AB 420, ab 420, Ab 80 and aB 80, recombinant frequency = (80 + 80)/1000 x 100 = 16%. Under a symmetric model each parental gamete is 42% and each recombinant 8%.

A recombination frequency near 50% can indicate unlinked loci or loci far apart on the same chromosome; it does not prove different chromosomes. Genetic map distances are a useful extension, but the core task is explaining departures from independent dihybrid ratios using linkage and crossing-over.

Step by step
  1. 1

    Parental genotypes in line notation

    A B above the double line and a b below, crossed with a b over a b.

  2. 2

    Circle the gametes and label them

    AB and ab are parental; Ab and aB are recombinant.

  3. 3

    Offspring genotypes and phenotypes

    Draw each offspring in line notation, state its phenotype, and label it parental or recombinant.

  4. 4

    Recombinant frequency

    Recombinant offspring / total offspring x 100.

Worked example

Work through the evidence

AB/ab is test-crossed with ab/ab. Recombination frequency is 10%. What are the four expected gamete probabilities?

One way to explain it

AB and ab are 45% each; Ab and aB are 5% each, assuming symmetric recovery and no viability differences.

Why this answer works
  • Recombinants sum to 10%.
  • The remaining 90% is split between parental classes.

Watch out for this

A student says: "Two linked genes can never be separated." What is wrong with this?

Show the answer

Crossing-over between the loci can generate recombinant combinations.

Check your understanding

Which are recombinant gametes from an AB/ab parent?

  1. Only AA and bb
  2. Ab and aB
  3. AB and ab, the parental combinations
Show the answer

Ab and aB

These combine alleles from different original homologues.

Exam-style questions

Check your understanding

A test cross of AaBb x aabb gives AB 410, ab 390, Ab 105, aB 95. Which conclusion is best supported?

  1. A and B are about 80 map units apart.
  2. A and B are completely linked.
  3. A and B assort independently.
  4. A and B are linked, about 20 map units apart.
Show the answer

A and B are linked, about 20 map units apart.

Parental classes far outnumber recombinants: (105 + 95) / 1000 = 20% recombination, so the genes are linked.

Quick recall

Card 1 of 3. Answer in your head, then check.

What do excess parental classes tell you about two loci?

You can return to this lesson any time.