9477 / 2027

Lesson 6 of 7 / Inheritance and genetic problems

Infer ratios from a pathway

Why can four genotype classes collapse into three phenotypes?

In this lesson: Solve epistasis problems from interactions between loci.

About 8 min

The key ideaA gene at one locus can mask the phenotypic effect of another; derive the ratio from the supplied biology instead of memorising it.

Build from gametes

Which step is blocked by the genotype?

Colourless precursorA worksBrown intermediateB worksPurple product9 purple : 3 brown : 4 white

A_B_ gives purple. A_B_ is purple (9/16); A_bb remains brown (3/16); aaB_ and aabb lack the first product and are white (4/16).

The ratios refer to AaBb x AaBb with independent loci and complete dominance at each locus. Gene interaction changes phenotype grouping; it does not change the underlying 9:3:3:1 genotype-class probabilities. A and B label functional enzyme-producing alleles in this model.

Explanation

Epistasis is an interaction in which a genotype at one locus masks or modifies the phenotypic expression of another locus. It differs from dominance, which describes the relationship between alleles at the same locus.

Consider a pigment pathway: enzyme A makes a brown intermediate from a colourless precursor, and enzyme B converts brown to purple. One functional dominant allele at each locus is sufficient for its enzyme. A_B_ is purple, A_bb is brown, and aa__ is colourless because the upstream step fails regardless of B.

In AaBb x AaBb with independent assortment, the underlying genotype groups are 9 A_B_, 3 A_bb, 3 aaB_ and 1 aabb. Applying the pathway combines the last two into colourless, giving 9 purple : 3 brown : 4 colourless. The ratio follows from the pathway, not from a new way of segregating chromosomes.

Other pathways produce other groupings. If both enzymes are required to make any coloured product and either recessive homozygote blocks it, only A_B_ is coloured, giving 9 coloured : 7 uncoloured. The syllabus emphasises interpreting information, not memorising a catalogue of special ratios.

Step by step
  1. 1

    Read the biochemical rule

    Identify which step each allele controls.

  2. 2

    Assign each genotype class

    Ask whether the relevant product can form.

  3. 3

    Combine matching phenotypes

    Add probabilities only after the biological grouping.

Worked example

Work through the evidence

In the brown-to-purple pathway, what is the phenotype of aaBB and why?

One way to explain it

Colourless: without functional A, the brown intermediate is not made, so B has no substrate to convert to purple.

Why this answer works
  • The upstream block masks the downstream genotype.
  • BB does not bypass the missing biochemical step.
Is this true? "Epistasis means an allele moves to a different chromosome."

It describes an interaction in phenotype, not a physical relocation of the gene.

Try a question

Which genotype is brown in the stated two-step pathway?
You can return to this lesson any time.