Topic 6 of 6
Manometers and pressure differences
A manometer uses the level difference in a connected liquid to compare two pressures. First identify which side's liquid surface is lower.
At the same horizontal level in a connected stationary liquid, pressure is equal. A vertical difference h gives a pressure difference of ρgh.
An open-end manometer has one arm connected to a gas and the other open to the atmosphere. The greater pressure pushes its side's liquid surface lower. The two surface pressures are therefore the gas pressure and the atmospheric pressure.
Compare the two liquid surfaces first
The same connected water has density 1000 kg/m3; g = 10 N/kg. The right-hand end is open to air at 101000 Pa.
Gas pressure is higher than atmospheric
Pressure difference = 1000 x 10 x 0.120 = 1200 Pa.
At A: gas pressure. At B: atmospheric pressure + 1200 Pa.
Gas pressure = 101000 + 1200 = 102200 Pa.
Gas pressure is lower than atmospheric
Pressure difference = 1000 x 10 x 0.120 = 1200 Pa.
At A: gas pressure + 1200 Pa. At B: atmospheric pressure.
Gas pressure = 101000 - 1200 = 99800 Pa.
The blue dashed line marks the equal-pressure reference level. Use the vertical level difference to compare pressures, then use the known atmospheric value.
Gas-side surface lower: add the difference
Choose the horizontal reference at the lower, gas-side surface. Its pressure is the gas pressure. At that same level in the open arm, the point is h below the atmosphere-exposed surface, so its pressure is atmospheric pressure plus ρgh.
Worked example
Gas pressure above atmospheric pressure
Use water density 1000 kg/m3, g = 10 N/kg, h = 0.120 m and atmospheric pressure 101000 Pa.
- Find the difference: ρgh = 1000 x 10 x 0.120 = 1200 Pa.
- Use the surface positions: the gas-side surface is lower, so gas pressure is greater.
- Add to the reference: pgas = 101000 + 1200 = 102200 Pa.
Gas-side surface higher: subtract the difference
Now the open-side surface is lower. At that horizontal level, atmospheric pressure equals the gas pressure plus the pressure of the liquid column below the higher gas-side surface:
pgas = patmosphere - ρghThe open end supplies the pressure reference. The sign follows from which surface is higher.
With the same supplied water density, g and 0.120 m separation, the difference is still 1200 Pa. Gas pressure is now 101000 - 1200 = 99800 Pa. The gas pressure is positive but lower than atmospheric pressure.
If both levels are equal, the pressure difference is zero. That means the gas and atmosphere have equal pressures, not that their pressures are both zero.
Measure the full vertical separation
Read both water menisci from the same vertical scale and use the bottom of each meniscus at eye level. Wait for a steady liquid. These example readings are consistent with the higher-gas-pressure case:
| Water surface | Height reading / mm |
|---|---|
| Gas side | 134 |
| Open side | 254 |
The separation is 254 - 134 = 120 mm = 0.120 m. Use the difference between the two surfaces, not the length around the U-bend or the movement of just one surface from an earlier position.
If h is overestimated, the magnitude of the pressure difference is overestimated. In the higher-gas-pressure case this makes the calculated gas pressure too high; in the lower-gas-pressure case it makes it too low because too much is subtracted. A vertical scale and eye-level readings address a specific measurement cause.
A difference needs a reference before it gives a gas pressure. The height and liquid density give ρgh. To find gas pressure relative to a vacuum, also use the atmospheric pressure or another supplied reference. Do not assume that ρgh alone is the absolute gas pressure.