K323 / 2027
Pressure overview

Topic 2 of 6

Density from measurements

Density is mass per unit volume. It tells us how much mass occupies a given amount of space.

Compare two samples that each occupy 10 cm3. If one has a mass of 27 g and the other 80 g, the second is denser: it has more mass in the same volume. A larger total mass alone does not show greater density when the volumes are different.

Mass is measured in g or kg; volume is measured in cubic units such as cm3 or m3. Review prefixes and volume conversions if needed. Density uses mass, not the weight in newtons.

Density = mass / volume
ρ = m / V
ρ (rho) = density; m = mass; V = volume. Use g with cm3 for a density in g/cm3, or kg with m3 for a density in kg/m3.

Density is a scalar quantity: it has no spatial direction. For a uniform material under the same conditions, doubling the volume doubles the mass, leaving the ratio m / V unchanged.

An irregular solid: measure the displaced volume

Use a balance to find the solid's mass. To find the volume of a suitable irregular solid, record the water volume in a measuring cylinder before and after fully submerging the solid. The increase is the solid's volume.

Measured mass of the irregular solid: 64.8 g

These are supplied cylinder readings. Fine scale divisions are omitted.

Before immersion

Before immersion: 38 cubic centimetresThe cylinder contains water. Its supplied lower-meniscus reading is 38 cubic centimetres. The mass of the solid is 64.8 grams. The two readings use the same cylinder scale; fine divisions are omitted.020406080Scale in cm338cm3

After full immersion

After full immersion: 62 cubic centimetresThe same cylinder contains water and a fully submerged irregular solid. Its supplied lower-meniscus reading is 62 cubic centimetres. The solid is completely below the water surface, with no trapped air or water loss. The mass of the solid is 64.8 grams. The two readings use the same cylinder scale; fine divisions are omitted.020406080Scale in cm362cm3

Solid volume = 62 - 38 = 24 cm3

Density = 64.8 / 24 = 2.7 g/cm3.

The supplied readings are 38 cm3 before and 62 cm3 after the solid is fully submerged. Its volume is the 24 cm3 increase, not the final reading of 62 cm3.
Direct readings for the irregular solid
Quantity and unitReading
Mass of solid / g64.8
Initial water volume / cm338
Final cylinder reading / cm362

Worked example

Calculate volume, then density

  1. Find the solid's volume: V = 62 - 38 = 24 cm3.
  2. Divide mass by this volume: ρ = 64.8 g / 24 cm3 = 2.7 g/cm3.

Each cubic centimetre of this uniform solid has a mass of 2.7 g. Dividing by 62 cm3 would include the original water as part of the solid's volume.

The solid must be fully submerged, insoluble and non-absorbing, with no water lost. Remove trapped air bubbles: they displace extra water, making the calculated volume too large and the calculated density too small. A floating object's submerged portion is not automatically its whole volume, so this simple method is unsuitable unless the whole solid can be measured correctly.

Choose a cylinder that fits the object and final level while still having useful divisions. Keep it upright and read the bottom of the water meniscus at eye level. The measurement methods page explains the reading technique.

Convert both parts of a density unit

Changing g/cm3 to kg/m3 changes both the mass unit and the volume unit.

1 g/cm3 = 0.001 kg / 0.000001 m3
= 1000 kg/m3
1 g = 0.001 kg. Also, 1 cm3 = (0.01 m)3 = 0.000001 m3.

Therefore 2.7 g/cm3 = 2700 kg/m3. Dividing 2.7 by 1000 would convert the grams but leave the cubic centimetres unchanged. That would give kg/cm3, not kg/m3.

A regular solid: calculate volume from its shape

For a cuboid, measure its mass and its three perpendicular dimensions. Its volume is length x width x height. Use an instrument with a suitable range and resolution for each dimension.

A separate regular sample

Measured mass: 64.8 g. Measure three perpendicular dimensions of the cuboid.

Volume from the dimensions of a cuboidA separate regular solid has a measured mass of 64.8 grams. Its three perpendicular dimensions are 4.0 centimetres, 3.0 centimetres and 2.0 centimetres. The front horizontal edge is labelled 4.0 centimetres, the receding edge is 3.0 centimetres and the vertical edge is 2.0 centimetres. Its volume is their product, 24 cubic centimetres, and its density is 2.7 grams per cubic centimetre. Use the supplied measured dimensions rather than measuring this perspective drawing.4.0 cm2.0cm3.0cm

Volume = 4.0 x 3.0 x 2.0 = 24 cm3

Density = 64.8 / 24 = 2.7 g/cm3.

This is a separate regular sample. Its supplied dimensions are 4.0 cm, 3.0 cm and 2.0 cm, and its mass is 64.8 g. The dimensions determine volume; do not measure the illustration on screen.

V = 4.0 x 3.0 x 2.0 = 24 cm3, so ρ = 64.8 / 24 = 2.7 g/cm3. Here geometry provides the volume that displacement provided for the irregular sample.

Measure the actual solid, not a surrounding container or gaps around it. Repeat dimension readings at different positions to judge small variations. If the shape is substantially irregular, assuming a cuboid can give a misleading volume; choose a suitable displacement method instead.

A liquid: subtract the container's mass

  1. Weigh a clean, dry, empty measuring cylinder, or zero the balance with the empty cylinder on it.
  2. Add the liquid and record its volume at eye level using the appropriate meniscus reading. Keep the outside of the cylinder dry.
  3. Weigh the cylinder and liquid. Subtract the empty cylinder's mass, unless it was correctly tared.
  4. Divide the liquid's mass by the volume of that same liquid.

For example, an empty cylinder has a mass of 42.6 g. With 50 cm3 of liquid inside, its mass is 82.6 g. The liquid's mass is 82.6 - 42.6 = 40.0 g, giving a density of 40.0 / 50 = 0.80 g/cm3.

Keep the mass and volume measurements matched. If liquid spills after the volume is recorded but before weighing, the smaller measured mass divided by the old volume gives too small a density. Liquid on the outside adds mass without adding to the measured inside volume, so it can make the density too large.

Worked example

Find a mass from a known density

A uniform liquid has density 0.80 g/cm3. What mass occupies 75 cm3?

  1. Rearrange ρ = m / V: m = ρV.
  2. Substitute consistent units: m = 0.80 g/cm3 x 75 cm3 = 60 g.

The cm3 units cancel, leaving grams. If volume were the unknown instead, rearrange to V = m / ρ.

Keep observations separate from calculations. Record the balance and cylinder readings with their units, then show the calculated liquid or solid volume and density. This makes a mistaken subtraction or unit conversion easier to find.

Optional check A 96 g insoluble solid is fully submerged without trapped air or water loss. The cylinder reading rises from 40 to 72 cm^3. What is its density?
A 96 g insoluble solid is fully submerged without trapped air or water loss. The cylinder reading rises from 40 to 72 cm^3. What is its density?