Topic 4 of 4
Real and virtual images
To classify an image, follow the rays first. Then compare the image's orientation and height with the object's.
A thin converging lens brings an axis-parallel beam to F. Rays from a nearby object point need not arrive parallel, so their meeting point can be elsewhere.
Actual convergence or apparent convergence?
- Real image
- Actual refracted rays from an object point meet at the image point. A screen placed there can show a sharp image.
- Virtual image
- The emergent rays diverge, but their backward extensions meet at an apparent image point. A screen at that apparent position cannot collect actual converging rays to form the image.
- Upright or inverted
- Compare orientation with the object. For the upright arrow examples, an image arrow below the axis is inverted; one above it is upright.
- Magnified, same size or diminished
- Compare image height with object height. A greater, equal or smaller height gives the corresponding description.
You can see both real and virtual images when the appropriate light enters your eye. A screen test concerns actual convergence, not visibility.
Read three completed diagrams
Each model uses a lens of focal length 8.0 cm and an upright object 2.0 cm tall. Identify which lines meet, then compare the image and object arrows.
Locate where rays, or their backward extensions, meet
Each completed diagram uses f = 8.0 cm and a 2.0 cm upright object. Horizontal and vertical distances have the same scale in all three panels. Use the supplied labels, not a ruler on your screen.
Blue and orange arrows represent the object and image. Green arrows show light travel. Dashed green lines are backward extensions.
A real, inverted, magnified image
The refracted rays meet at the image position. A screen placed there can receive a sharp image.
A real, inverted, diminished image
The refracted rays meet at the image position. A screen placed there can receive a sharp image.
A virtual, upright, magnified image
Only the backward extensions meet. The apparent image is on the object's side of the lens; the emerging light travels to the right.
- First diagram: real, inverted and magnified
- The actual rays meet 24 cm on the far side of the lens, 4 cm below the axis. The image is inverted and twice the 2 cm object height.
- Second diagram: real, inverted and diminished
- The rays meet 12 cm on the far side, 1 cm below the axis. The image is inverted and half the object height.
- Third diagram: virtual, upright and magnified
- Backward extensions meet 8 cm on the object's side, 4 cm above the axis. The actual emergent rays diverge. The image is upright and twice the object height.
These descriptions come from the completed ray paths and labelled sizes. The same converging lens can produce different image characteristics; it does not always magnify.
Find an image and describe what you observe
For a real-image investigation, align an illuminated arrow, the lens and a screen along the principal axis. Move the screen until the image is sharp. Measure the image distance from the lens centre, then compare image height and orientation with the object. Use the same length units for a size comparison.
Move the object to another suitable position and refocus the screen. Keep the alignment and distinguish the lens-to-object distance from the lens-to-screen distance. A millimetre ruler can measure positions and heights, but a blurred edge limits how precisely the image height can be read.
For a supplied arrangement known to produce a virtual image, look through the lens at the object and describe the apparent image. It can be seen even though a screen at the apparent position does not show it. Its image position may be inferred from backward ray extensions.
A blurred screen is not proof of a virtual image. The screen may simply be in the wrong place or the apparatus misaligned. Use the ray behaviour and the stated setup as evidence.