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Periodicity and Metals

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Periodicity and Metals

Find patterns in the Periodic Table and use evidence to predict reactions.

O-Level 6092 (2026) / SEC G3 K324 (2027)

01

Read position from electron arrangement

Proton number orders the table; outer electrons explain recurring behaviour.

The Periodic Table orders elements by increasing proton number. A period is a horizontal row; a group is a vertical column. For the first twenty elements, occupied electron shells give the period. Main-group elements in one group have the same number of outer electrons, which explains similar chemical reactions.

Worked example

Locate an element

An atom has 17 protons and electron arrangement 2,8,7. Locate it and predict its character.

  1. Seventeen protons identify chlorine.
  2. Three occupied shells put it in period 3.
  3. Seven outer electrons place it in group 17; it is a non-metal.
Answer

Period 3, group 17. It behaves similarly to other halogens because their outer shells have the same electron count.

Across a period, character generally changes from metallic on the left to non-metallic on the right. Metals with few outer electrons tend to lose them; non-metals with nearly full outer shells tend to gain or share electrons. Group 18 has full outer shells, including helium with two rather than eight.

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Common simple-ion patterns among the first twenty elements
Outer electronsTypical changeExamples
1 or 2Lose 1 or 2Na+, K+; Mg2+, Ca2+
3 in aluminiumLose 3Al3+
5, 6 or 7 in suitable non-metalsGain 3, 2 or 1N3-; O2-, S2-; F-, Cl-
Full shellNo usual simple-ion formationHe, Ne, Ar
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Check your understandingWhy do sodium and potassium have similar chemistry despite having different proton numbers?Think it through, then reveal the answer
Both have one outer-shell electron and commonly lose it in reactions. Their different numbers of occupied shells help explain differences in reactivity.
02

Group 1: lithium, sodium and potassium

Similar products, increasingly vigorous reaction with water.

Lithium, sodium and potassium are relatively soft, low-density metals. Their melting points decrease down this sequence, while their reactions with cold water become more vigorous. Low density is a shared property; do not assume density follows a perfectly steady trend.

Reaction with cold water
MetalTypical observationProducts
LithiumFloats and fizzes steadilyLithium hydroxide and hydrogen
SodiumFloats, moves and may melt into a ball as heat is releasedSodium hydroxide and hydrogen
PotassiumReacts very vigorously; hydrogen may ignitePotassium hydroxide and hydrogen

For sodium: 2Na(s) + 2H2O(l) -> 2NaOH(aq) + H2(g). The resulting solution is alkaline because it contains hydroxide ions. The shared outer electron explains the common product pattern. Use observed trends to predict an unfamiliar group-1 element, while treating predicted observations as predictions rather than measured facts.

Check your understandingBased on the lithium-to-potassium trend, predict how an element below potassium might compare.Think it through, then reveal the answer
It would be expected to react more vigorously with water and have a lower melting point. Its hydroxide and hydrogen would be expected products; exact rates or temperatures cannot be inferred from the trend alone.
03

Group 17: identify displacement from the evidence

A more reactive halogen oxidises a less reactive halide.

Halogens at room temperature
ElementForm, state and appearanceRelative reactivity
ChlorineCl2, pale green gasMost reactive of these three
BromineBr2, red-brown liquidIntermediate
IodineI2, grey-black solid; purple vapour on heatingLeast reactive of these three

Down the group, colour becomes darker and melting/boiling points rise, giving the gas-liquid-solid sequence. All three are diatomic non-metals with seven outer electrons. Their displacement reactivity decreases down the group.

Halogen added to a halide solution
Added halogenChloride solutionBromide solutionIodide solution
ChlorineNo displacementBromine formsIodine forms
BromineNo displacementNo displacementIodine forms
IodineNo displacementNo displacementNo displacement

Cl2(aq) + 2Br-(aq) -> 2Cl-(aq) + Br2(aq). The orange/brown bromine colour is evidence of displacement. Chlorine or bromine added to iodide can produce brown aqueous iodine; distinguish solution colours from the colours of pure elements.

Check your understandingHalogen X displaces bromine from bromide but bromine cannot displace X from its halide. What follows?Think it through, then reveal the answer
X is more reactive than bromine. Among chlorine, bromine and iodine, X fits chlorine. The direction of displacement determines the order.
04

Recognise noble gases and transition metals

Electron arrangement explains one family; characteristic properties identify another.

Group 18 elements have filled outer shells, making them chemically unreactive under ordinary conditions. Helium has two outer electrons; neon and argon have eight. They do not need to gain, lose or share electrons to reach this stable arrangement.

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Noble gases exist as single atoms. Argon supplies an inert atmosphere in filament lamps and in steel manufacture, helping prevent unwanted oxidation. Neon is used in discharge lighting. Helium is useful in balloons because it is low-density and unreactive.

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Typical transition-element properties
PropertyExample or significance
High melting point and densityUseful metal properties; compare with softer, low-density group-1 metals
Variable oxidation statesIron forms Fe2+ and Fe3+ compounds
Coloured compoundsCopper(II) solutions are often blue; iron compounds show different colours
Catalytic activityIron in ammonia synthesis; nickel in hydrogenation; manganese(IV) oxide catalysing hydrogen peroxide decomposition
Check your understandingHelium has only two electrons. Why is it still unreactive?Think it through, then reveal the answer
Its first shell is full with two electrons. The relevant idea is a filled outer shell, not a rule that every stable atom must have eight outer electrons.
05

Build the metal reactivity series from experiments

More reactive metals form positive ions more readily.

The prescribed order is K, Na, Ca, Mg, Zn, Fe, Pb, H, Cu, Ag, from most to least reactive. Hydrogen is a reference point, not a metal. Compare reactions under the same conditions: a larger surface area or higher temperature can make a reaction look faster without changing the underlying reactivity order.

Evidence from water and dilute hydrochloric acid
MetalsWater or steamDilute HCl
K, Na, CaReact with cold water; hydroxide and hydrogen formVery vigorous reaction; acid is not a suitable routine comparison
MgVery slow with cold water; heated magnesium reacts with steam to give MgO and H2Reacts readily
Zn, FeReact with steam when strongly heatedReact to give a chloride and hydrogen
PbNo appreciable reaction with water or steam in the usual school comparisonReaction may be slow or stop as insoluble PbCl2 coats the surface
Cu, AgNo reaction with water or steamDo not liberate hydrogen
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A higher position in the metal reactivity series means a greater tendency of a metal atom to lose electrons and form its positive ion. In an aqueous displacement, the added metal is oxidised and the displaced metal ion is reduced. In an oxide displacement, the more reactive metal takes oxygen from the less reactive metal oxide. Use the stated conditions: very reactive metals in water may react mainly with water instead of providing a clean displacement comparison.

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A more reactive metal displaces a less reactive one from its aqueous ions: Fe(s) + Cu2+(aq) -> Fe2+(aq) + Cu(s). Iron loses electrons; copper ions gain them. A more reactive metal can also remove oxygen from a less reactive metal oxide, for example Mg(s) + CuO(s) -> MgO(s) + Cu(s) on heating.

Worked example

Deduce an order without memorising it

Under comparable conditions, A reacts rapidly with dilute HCl, B reacts slowly, and C does not react.

  1. The evidence places A and B above hydrogen and C below it, assuming no passivating coating.
  2. The rates suggest A is more reactive than B, but comparable surface area and temperature matter.
  3. A displacement experiment can give additional evidence.
Answer

A > B > H > C is supported under the stated conditions. Surface coatings, such as on lead, can complicate rate comparisons.

Check your understandingWhy does copper not produce hydrogen with dilute hydrochloric acid?Think it through, then reveal the answer
Copper is below hydrogen in the reactivity series, so it does not displace hydrogen under these conditions. This does not mean copper never reacts with any acid.
06

Use reactivity to explain extraction and heating

Strongly bound compounds of reactive metals are harder to break down.

An ore contains a metal compound in a form worth extracting. More reactive metals generally need more demanding extraction. Carbon can reduce oxides of metals below it in the relevant series, such as zinc, iron, lead and copper, when heated appropriately. Very reactive metals such as potassium, sodium, calcium and magnesium require other methods, commonly electrolysis of suitable molten compounds. This is a principle, not a requirement to memorise every industrial furnace.

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Pure: reduction experiments provide evidence for the series. Carbon reduces copper(II) oxide: 2CuO(s) + C(s) -> 2Cu(s) + CO2(g). Hydrogen also reduces suitable oxides: CuO(s) + H2(g) -> Cu(s) + H2O(g). Oxides resisting a given reducing agent under comparable conditions point to more reactive metals. Use supplied results and conditions; the hydrogen reference for dilute-acid reactions is not a universal oxide-reduction cutoff.

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Representative oxide-reduction results under suitable school-laboratory heating
Metal in the oxideHeated with carbonHeated in hydrogen
K, Na, Ca, MgNot readily reduced under these conditionsNot readily reduced under these conditions
ZnCan be reducedNot readily reduced in the usual school comparison
Fe, Pb, CuCan be reducedCan be reduced with suitable heating
AgSilver oxide decomposes on heating aloneA heated-silver result alone cannot prove reduction by hydrogen
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Worked example

Combine reaction evidence rather than over-reading one test

Carbon reduces ZnO and CuO under suitable heating but not MgO. Zinc displaces copper from aqueous copper(II) sulfate. What relative order follows?

  1. MgO resisting carbon while ZnO is reduced places magnesium above zinc in this comparison.
  2. Both ZnO and CuO being reduced by carbon does not distinguish zinc from copper.
  3. Zinc displacing Cu2+ supplies that missing comparison: zinc forms Zn2+ more readily than copper forms Cu2+.
Answer

Mg > Zn > Cu. A successful reduction test places a metal relative to the reducing agent; combine it with other tests to resolve the full order. Heating conditions matter, and hydrogen reducing iron oxide does not put iron below hydrogen in the dilute-acid series.

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Heating metal carbonates
CarbonatesExpected pattern
Potassium and sodiumStable under ordinary laboratory heating
Calcium, magnesium, zinc, iron(II), lead(II), copper(II)Generally decompose on sufficient heating to metal oxide and CO2; more reactive metal usually means greater thermal stability
SilverLow thermal stability; carbonate first loses carbon dioxide and its unstable oxide then gives silver and oxygen. Overall: 2Ag2CO3(s) → 4Ag(s) + 2CO2(g) + O2(g).
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For example, CuCO3(s) -> CuO(s) + CO2(g): green carbonate becomes black oxide, and the gas turns limewater milky. Calcium carbonate needs stronger heating than copper carbonate. Compare onset temperatures under controlled conditions rather than just how soon bubbles were noticed.

Check your understandingWhy is heating magnesium oxide with carbon not the usual way to extract magnesium?Think it through, then reveal the answer
Magnesium is more reactive than carbon in this comparison, so carbon cannot readily remove its oxygen. Electrolysis of a suitable molten magnesium compound is a more appropriate extraction principle.
07

Prevent rust by removing a condition or supplying protection

Rusting needs both oxygen and water.

Iron rusts when oxygen and water are both available. In a fair comparison, iron exposed to dry air lacks water; iron in boiled water protected by an oil layer lacks fresh oxygen; iron in ordinary water exposed to air has both. The last sample rusts. The controls isolate the conditions rather than showing that water alone is sufficient.

Painting, greasing and plastic coating provide a barrier to oxygen and water. Protection fails at a scratch if the exposed iron can contact both. The coating must remain intact and suit the object: grease can protect moving metal parts where paint would be unsuitable.

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Galvanising coats iron with zinc. It forms a barrier, and zinc is also more reactive than iron, so zinc can corrode preferentially even near a scratch. Sacrificial protection deliberately attaches a more reactive metal to iron; magnesium blocks attached to underwater pipes lose electrons and are consumed instead of the iron. They must be replaced periodically.

Check your understandingIron in a dry tube of air does not rust. Does this prove oxygen is unnecessary?Think it through, then reveal the answer
No. Oxygen is present but water is absent, showing that oxygen alone is insufficient. Compare with wet iron exposed to air to establish the need for both conditions.

Quick revision

Revisit the essentials, then return to an explanation when you need it.

Groups share valence-electron patterns. Group 1 becomes more reactive down the group; group 17 becomes less reactive. Noble gases have full outer shells.

Metal order: K, Na, Ca, Mg, Zn, Fe, Pb, H, Cu, Ag. Use comparable experiments. Rusting needs oxygen and water; barriers remove contact with them.

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Pure: connect displacement to electron loss, compare oxide reduction and carbonate stability, and distinguish sacrificial protection from an intact barrier.

Scope and references

Learning outcomes and sources

8. Periodicity and Metals (6092 / K324). Use the outcome map to find the explanation for a particular syllabus requirement.

See the learning outcome map
  1. 8.1(a) Order elements by proton number

    • Increasing atomic number

    Read position from electron arrangement

  2. 8.1(b) Relate position and electron arrangement

    • Periods and occupied shells
    • Proton number

    Read position from electron arrangement

  3. 8.1(c) Relate valence electrons and ion charge

    • First twenty elements
    • Common simple ions and limitations

    Read position from electron arrangement

  4. 8.1(d) Explain group similarity

    • Same valence electron count

    Read position from electron arrangement

  5. 8.1(e) Describe metallic-to-non-metallic trend

    • Across a period

    Read position from electron arrangement

  6. 8.1(f) Relate outer electrons to character

    • Electron loss, gain and sharing

    Read position from electron arrangement

  7. 8.1(g) Predict group properties

    • Group 1 and group 17

    Group 1: lithium, sodium and potassiumGroup 17: identify displacement from the evidence

  8. 8.2(a) Compare alkali metals

    • Li, Na, K
    • Softness and low density
    • Melting-point and water-reaction trends

    Group 1: lithium, sodium and potassium

  9. 8.2(b) Compare halogens

    • Cl2, Br2, I2
    • Diatomic forms, colours and states
    • Halide displacement

    Group 17: identify displacement from the evidence

  10. 8.2(c) Describe noble-gas forms and uses

    • Monoatomic, inert
    • Argon/neon lighting
    • Helium balloons
    • Argon steel manufacture

    Recognise noble gases and transition metals

  11. 8.2(d) Explain noble-gas unreactivity

    • Full outer shells

    Recognise noble gases and transition metals

  12. 8.3(a) Recognise transition properties

    • High melting point/density
    • Variable oxidation states
    • Coloured compounds

    Recognise noble gases and transition metals

  13. 8.3(b) Recognise catalytic uses

    • Transition elements and compounds

    Recognise noble gases and transition metals

  14. 8.4(a) Order prescribed metals

    • K, Na, Ca, Mg, Zn, Fe, Pb, H, Cu, Ag
    • Water, steam, dilute HCl
    • Carbon/hydrogen reduction of oxides

    Build the metal reactivity series from experimentsUse reactivity to explain extraction and heating

  15. 8.4(c) Deduce reactivity from data

    • Comparable experiments
    • Confounding factors

    Build the metal reactivity series from experiments

  16. 8.4(e) Relate extraction to reactivity

    • Ease of obtaining metals from ores

    Use reactivity to explain extraction and heating

  17. 8.4(f) Explain rusting and barriers

    • Oxygen plus water
    • Painting, greasing, plastic coating
    • Galvanising

    Prevent rust by removing a condition or supplying protection

  18. 8.4(b) Explain displacement using ion formation

    • Aqueous metal ions
    • Metal oxides

    Build the metal reactivity series from experiments

  19. 8.4(d) Relate carbonate stability to reactivity

    • Heating prescribed metal carbonates
    • Decomposition observations

    Use reactivity to explain extraction and heating

  20. 8.4(g) Explain sacrificial protection

    • More reactive metal corrodes
    • Magnesium on underwater pipes

    Prevent rust by removing a condition or supplying protection