Skip to notes
Polymers and Organic Chemistry

Topic 1 of 12

Formulae and names

A formula must show which atoms are joined, not just how many there are.

A-Level 8873, revised syllabus (2026-2027)

Read and name an organic structure

A formula must show which atoms are joined, not just how many there are.

An organic structure is a map of connections. A functional group is the atom or group of atoms responsible for a characteristic set of reactions. First find the functional group; then identify the carbon skeleton. The same molecular formula can describe compounds with different connections and therefore different chemistry.

Five ways to describe lactic acid
RepresentationWhat it tells you
Empirical: CH2OThe simplest whole-number atom ratio, C:H:O = 1:2:1.
Molecular: C3H6O3The actual numbers of atoms in one molecule.
Structural: CH3CH(OH)CO2HThe middle carbon bears OH; the final carbon belongs to COOH. Brackets keep the connectivity unambiguous.
DisplayedEvery atom and bond is shown, including each C-H and O-H bond.
SkeletalCarbon atoms are implicit at line ends and corners; enough attached hydrogen atoms are implied to give each carbon four bonds. Heteroatoms and their attached hydrogens, such as OH, are shown.

To turn a condensed formula into a displayed formula, draw the carbon skeleton first, then expand every bracketed group at its stated attachment point. Replace COOH by C(=O)-O-H and CHO by C(=O)-H. Finally add each C-H bond explicitly and check that each ordinary neutral carbon has four bonds, each oxygen two, and each hydrogen one. In a skeletal formula, apply the same valency check to recover the hidden C-H bonds.

A displayed formula keeps every atom visible

Three carbons form a chain. The first has three hydrogens; the second has one hydrogen and an OH group; the third has a double-bonded oxygen and an OH group. There are three carbons, six hydrogens and three oxygens.

COOH contains a C=O bond and a C-O-H group; it is not a carbon joined to three oxygens.

The same molecule in skeletal form

The left endpoint is CH3, the middle corner is CH attached to an explicit OH, and the right corner is the carboxyl carbon with C=O and OH. It represents the same lactic-acid connectivity as the displayed formula.

Count a carbon at every unlabelled end or corner. Do not count the end labelled O or OH as another carbon.
Recognise the whole group, then name an example
Class and general structureExample and naming cue
Alkane: CnH2n+2 for an acyclic saturated hydrocarbonCH3CH3, ethane; suffix -ane.
Alkene: CnH2n for an acyclic hydrocarbon with one C=CCH2=CHCH3, propene; locate the C=C and use -ene.
Benzene: C6H6, a six-carbon aromatic ringUse a hexagon containing a circle to represent the delocalised ring. A fully displayed benzene ring is not required.
Halogenoalkane: R-X; CnH2n+1X for a saturated acyclic monohalogen compoundCH3CH2Br, bromoethane; fluoro-, chloro-, bromo- or iodo- gives the substituent.
Alcohol: R-OH; CnH2n+2O for a saturated acyclic monohydric alcoholCH3CH(OH)CH3, propan-2-ol; number the OH position.
Aldehyde: R-CHO; CnH2nO for a saturated acyclic monoaldehydeCH3CHO, ethanal; the carbonyl carbon has at least one H, and its carbon counts in the chain.
Ketone: R-CO-R'; CnH2nO for a saturated acyclic monoketoneCH3COCH3, propanone; the carbonyl carbon is bonded to two carbon groups.
Carboxylic acid: R-COOH; CnH2nO2 for a saturated acyclic monocarboxylic acidCH3COOH, ethanoic acid; the COOH carbon is carbon 1.
Ester: R-COO-R'; CnH2nO2 for a saturated acyclic monoesterCH3COOCH2CH3, ethyl ethanoate; name the O-attached alkyl group first, then the acid-derived -oate part.
Amine: R-NH2 for a primary amine; N can also carry further carbon groupsCH3CH2NH2, ethylamine (ethanamine). For a saturated acyclic monoamine, CnH2n+3N.
Amide: R-CONH2; N-substituted forms include R-CONHR'CH3CONH2, ethanamide; C=O is directly attached to N. A saturated acyclic monoamide has CnH2n+1NO.
Amino acid: contains both NH2 and COOH; an alpha-amino acid is H2N-CH(R)-COOHH2NCH2COOH, aminoethanoic acid; the amino group is on the carbon next to COOH. For a saturated acyclic compound with one of each group: CnH2n+1NO2.

Here R and R' represent carbon-containing groups; they need not be identical. In methanal and methanoic acid, the group attached to the carbonyl carbon can be H instead. General molecular formulae apply only with the stated restrictions: rings, extra double bonds or extra functional groups change them. A formula alone does not establish the family; for example, propanal and propanone both have C3H6O.

For straightforward names, choose a parent chain containing the principal functional group and number it to locate that group or the double bond with a low number. The prefixes meth-, eth-, prop-, but-, pent- and hex- indicate 1-6 carbons. Show branches and substituent positions: CH3CH(CH3)CH2OH is 2-methylpropan-1-ol. Count the carbon attached to OH as carbon 1; the methyl branch is then on carbon 2.

Primary, secondary and tertiary classify the carbon carrying OH
Alcohol classCarbon groups attached to the OH-bearing carbonExample
PrimaryOne carbon group; methanol is conventionally treated with primary alcohols.CH3CH2OH
SecondaryTwo carbon groups.CH3CH(OH)CH3
TertiaryThree carbon groups.(CH3)3COH
Check your understandingName CH3CH2COOCH3 and identify its two carbon fragments.Think it through, then reveal the answer
Methyl propanoate. The O-attached CH3 group gives methyl; CH3CH2COO- contains three carbons including the carbonyl carbon, so it gives propanoate. Reversing these fragments would describe a different ester.