Topic 6 of 9
Forces between parallel currents
Each current-carrying wire produces a magnetic field at the other wire. Use that other-wire field to find each force; the source field and the responding conductor must be named separately.
Place two long parallel wires vertically in the page, wire 1 on the left and wire 2 on the right. Let both conventional currents initially point up. At wire 2, wire 1 produces a field into the page. An upward current in that field experiences a force left, towards wire 1.
At wire 1, wire 2's field is out of the page, so its upward current experiences a force right. Both forces point inward: parallel currents attract. These are paired forces on different wires, not two forces to add on one selected wire.
Parallel currents: the wires attract
Teal dot/cross symbols show the field made by the other wire at that location. Brown arrows show current. The two forces are equal and opposite despite the unequal currents and local fields; the considered length is 0.500 m.
Reverse one current: the wires repel
Teal dot/cross symbols show the field made by the other wire at that location. Brown arrows show current. The two forces are equal and opposite despite the unequal currents and local fields; the considered length is 0.500 m.
After reversing wire 2's current, wire 1's field at wire 2 remains into the page, but the reversed current now feels force right. Wire 2's field at wire 1 changes to into the page, giving the unchanged upward current a force left. Thus antiparallel currents repel. This follows from the field and force rules, not from treating currents as north or south poles.
Different currents, equal force magnitudes
Use I1 = 4.00 A, I2 = 3.00 A, separation d = 0.0200 m and a considered common length l = 0.500 m, away from the wire ends. With μ0 = 4π × 10-7 H/m:
= 4.00 × 10-5 T
Fon 2 = B1 at 2I2l
= (4.00 × 10-5)(3.00)(0.500)
= 6.00 × 10-5 N
For parallel upward currents this force is left. Calculate the partner using the other source:
= 3.00 × 10-5 T
Fon 1 = B2 at 1I1l
= (3.00 × 10-5)(4.00)(0.500)
= 6.00 × 10-5 N
The local source fields are unequal, yet the forces are equal and opposite. Combining the two relationships gives a useful result for these long parallel wires:
The symmetric product I1I2 explains the equal magnitudes. Reversing one current changes attraction to repulsion while leaving the magnitudes unchanged if both current magnitudes and the geometry stay fixed.