Chapter revision
Revision summary
Key ideas, equations and common mistakes. Open any topic below for the full explanation.
Name the source field, the selected body and the direction of conventional current or particle velocity. Calculate a force magnitude and a direction, then choose the motion or measurement model.
Uniform electric motion
Signed component: Fy = QEy
ay = Fy/m
A positive charge is forced along E and a negative charge against E, including when initially stationary. With perpendicular entry and no other significant force, the field-perpendicular velocity component is constant while the field-parallel component changes. The path is parabolic and total speed can change. Outside the ideal field, continue along the exit tangent.
Field patterns and directions
- Long straight wire: concentric field circles; right thumb follows current and curled fingers give B. Out-of-page current gives anticlockwise field in that view.
- Flat circular coil: central axial field with external return paths. Anticlockwise current seen at a face gives central field towards that observer.
- Long solenoid: approximately uniform interior away from ends, with weaker returning field outside. The grip-rule thumb gives the interior direction and points towards its north end.
Field lines are not particle tracks. A dot means the labelled quantity points out of the page and a cross means into it. Distinguish the views before comparing a face diagram with an axial section.
Conductor force and the current balance
B = F/(Il) for a perpendicular active length
The angle is between conventional current and the external B. Fleming's left-hand rule uses first finger for field, second for conventional current and thumb for conductor force; use the current's perpendicular component for a non-right angle. Parallel or antiparallel current gives zero force. Reversing one of I or B reverses the force; reversing both restores it.
In the shown current balance, an upward wire force produces a downward reaction on the separately weighed magnet. Convert its baseline-subtracted display change from grams to kilograms and use F = gΔm for the stated upward wire-force reference. At fixed perpendicular length, the F-against-I gradient is Bl, so divide by l to obtain B.
Keep supports separate, return wires outside the active field and geometry fixed. Check current-off drift, ranges, resolution, heating, fringing and contact forces. A changed balance display is not a changed physical mass; actual nonzero intercepts and anomalies need investigation.
Magnetic motion and velocity selection
Perpendicular uniform-field circle:
B|Q|v = mv2/r so r = mv/(|Q|B)
For positive-charge motion, use the conventional-current force direction; reverse it once for a negative charge with the same velocity. A stationary charge or velocity parallel to B gives zero magnetic force. Magnetic force does no work: it changes velocity direction while speed remains constant. It is the inward force, not an extra force in addition to a centripetal force.
For the electron semicircle in x > 0, the exit lies 2r below entry and its velocity is left. Radius and entry-to-exit separation are different. Outside the ideal field, the path is a straight tangent.
|Q|E = B|Q|v so v = E/B
This requires the intended incident direction, mutually perpendicular velocity and fields, and nonzero charge. The selected speed is independent of mass and charge magnitude. Off-speed force comparisons give the initial deflection, not automatically a full path or a process that brings every particle to the selected speed.
Quantity and unit reference
| Quantity | Symbol | SI unit |
|---|---|---|
| Electric charge | Q | C = A s |
| Elementary-charge magnitude; electron charge is -e | e | C |
| Particle mass; electron mass | m; me | kg |
| Electric field strength | E | N/C = V/m |
| Magnetic flux density | B | T = N/(A m) |
| Magnetic flux | Φ | Wb = T m2 = V s |
| Force | F | N |
| Current | I | A |
| Active conductor length | l | m |
| Speed | v | m/s |
| Path radius | r | m |
| Balance display change, converted to kg | Δm | kg |
The supplied electron constants are e = 1.60 × 10-19 C and me = 9.11 × 10-31 kg. Convert 1 mT = 10-3 T, 1 µT = 10-6 T, 1 µWb = 10-6 Wb, 1 ns = 10-9 s and 1 g = 10-3 kg before using SI equations.
For the supplied uniform perpendicular-area example, Φ = BA: local B and the flux through an area are distinct quantities. The units are 1 T = 1 kg s-2 A-1 and 1 Wb = 1 kg m2 s-2 A-1.
Review a topic
- Motion in a uniform electric field
- Magnetic sources and field patterns
- Force on a current-carrying conductor
- Measure magnetic flux density
- Magnetic force on a charged particle
- Circular motion in a magnetic field
- Select a beam speed