Full chapter
Rate of Reactions
Explain why reactions speed up, and read what a progress graph actually proves.
O-Level 6092 (2026) / SEC G3 K324 (2027)
Explain a rate change using collisions
Changing a condition changes how often particles react.
Reaction rate measures how quickly a reactant is used up or a product forms. Reacting particles must collide, and collisions must have enough energy to lead to reaction. An explanation should connect the changed condition to particle behaviour, then to the number of successful collisions per unit time.
| Change | Particle explanation | Important control |
|---|---|---|
| Higher solution concentration | More reacting particles per unit volume; more frequent collisions | Keep total solution volume and temperature controlled |
| Higher gas pressure at fixed temperature | Gas particles are closer together; more collisions per unit volume per second | Applies to gaseous reactants, not simply pressing on a solid |
| Smaller solid pieces, same total mass | Greater exposed surface area offers more places for collisions | Grinding does not create more total moles of solid |
| Higher temperature | Particles move faster and collide more energetically; more successful collisions | Do not explain temperature solely as an increase in concentration |
A larger lump and equal-mass powder can produce the same final amount of gas while reacting at different speeds. In contrast, adding more of a limiting reactant can change the final amount. Keep the question "how fast?" separate from "how much?".
Check your understandingWhy does powdered calcium carbonate react faster than equal-mass chips in excess acid?Think it through, then reveal the answer
Choose a changing quantity
Match the measurement to the reaction.
| Measurement | Suitable situation | Rate evidence |
|---|---|---|
| Gas volume against time | Gas-producing reaction; gas can be collected | Volume increase per unit time |
| Mass against time | A gas escapes from an open reaction vessel | Mass loss per unit time |
| Time to a fixed visible endpoint | A precipitate obscures a mark or a colour reaches a chosen endpoint | Shorter time means a faster average approach to that same endpoint |
For a gas syringe, check airtight connections and free plunger movement. For mass loss, prevent splashes so that lost liquid is not mistaken for escaped gas. Start timing consistently. A subjective colour or visibility endpoint is less precise than a clear instrumental measurement, so use the same criterion and repeat.
Worked example
Calculate an average rate
A reaction produces 36 cm3 of gas in its first 40 s.
- Average rate = change in gas volume / time interval.
- 36/40 = 0.90 cm3 s-1.
- This is an average over 40 s; the rate may have fallen throughout that interval.
0.90 cm3 s-1. State both interval and units.
Check your understandingTwo experiments reach the same endpoint in 20 s and 40 s. Which is faster?Think it through, then reveal the answer
Read slope and final amount separately
A plateau means product formation has stopped, not that nothing happened.
Same yield, different rates
The faster experiment reaches 44 cubic centimetres earlier; both finish at the same volume.
The gradient of a product-volume graph gives rate. A steeper initial slope means faster initial reaction. The curve becomes less steep as reactants are consumed. A horizontal line means no further gas is collected; a reactant may have been exhausted. A tangent estimates the instantaneous rate at a point; a line joining two measured points gives the average over that interval.
For a mass-loss graph, the mass decreases, so the slope is negative. Use the magnitude of the decrease per time for a positive reaction-rate value. Compare final gas volumes only at the same temperature and pressure. A leak can reduce apparent volume without changing the actual chemical yield.
Worked example
Diagnose a changed curve
A repeat reaches its plateau sooner but at the same final volume. What can be concluded?
- It formed the measured product more quickly.
- The same final amount formed under the stated gas conditions.
- A rate factor such as temperature, concentration or surface area may explain it; the curve alone does not identify which.
Faster rate, same final amount. Do not claim that a catalyst or temperature change is uniquely proved.
Check your understandingA lower plateau appears after a bung leaks. Does that prove less product formed chemically?Think it through, then reveal the answer
Catalysts provide an easier reaction pathway
They change the rate without being used up overall.
A catalyst increases reaction rate and is chemically unchanged overall at the end. It can take part in intermediate steps before being regenerated. It provides an alternative pathway with lower activation energy, so a larger fraction of collisions can succeed at the same temperature. It does not supply the reaction energy or increase the final yield from a fixed limiting reactant.
| Context | Catalyst or catalytic material |
|---|---|
| Haber ammonia synthesis | Iron |
| Hydrogenation of unsaturated oils | Nickel |
| Hydrogen peroxide decomposition | Manganese(IV) oxide |
| Sulfuric-acid manufacture | Vanadium(V) oxide, an example of a compound acting as an industrial catalyst |
| Catalytic converters | Metal catalysts speed conversion of exhaust pollutants |
| Biological reactions | Enzymes are biological catalysts |
On an energy profile, the catalysed route has a lower peak but the same reactant and product levels. Enzymes also increase rates, but their activity depends on conditions; heating them too much can change their structure and reduce activity. Do not treat every catalyst as able to work under any conditions.
Check your understandingAdding a catalyst gives more gas after 20 s. Must it give more gas after the reaction is complete?Think it through, then reveal the answer
Plan a fair rate investigation
A plan must say how the measurements will support a conclusion.
- Independent variable
Prepare a range of acid concentrations by measured dilution, keeping total solution volume equal.
- Controls
Use equal magnesium masses and exposed areas, the same initial temperature and the same apparatus.
- Measurements
Record hydrogen volume at fixed times after mixing; repeat each concentration.
- Analysis
Plot volume-time curves and compare initial gradients, with units. A repeat checks reproducibility.
- Practical precautions
Keep away from ignition sources because hydrogen is flammable; use suitable eye protection and avoid a sealed vessel without a free gas outlet.
To investigate particle size instead, vary chip/powder size while holding carbonate mass and acid concentration/volume constant. Use acid in excess if you want final gas amount fixed by carbonate. A suitable method controls the variables that could give the same observed effect, not just the easiest variables to measure.
Check your understandingA student compares hot powdered carbonate with cold chips. Can the difference be attributed to temperature?Think it through, then reveal the answer
Quick revision
Revisit the essentials, then return to an explanation when you need it.
Rate describes change per unit time. Concentration, pressure, temperature and exposed surface area affect successful collisions. On a progress graph, slope indicates rate and the final level indicates measured amount.
Pure: a catalyst lowers the activation barrier and is regenerated. A fair investigation changes one variable, controls alternatives and states how data will be analysed.
Scope and references
Learning outcomes and sources
10. Rate of Reactions (6092 / K324). Use the outcome map to find the explanation for a particular syllabus requirement.
See the learning outcome map
10(a) Explain rate factors
- Concentration
- Gas pressure
- Particle size/surface area
- Temperature
- Collisions between reacting particles
10(b) Define catalysts and their effects
- Rate increase
- Chemically unchanged overall
- Enzymes included
10(c) Explain lower activation energy
- Alternative pathway
- More successful collisions
10(d) Recognise catalyst applications
- Industrial processes
- Enzymes as biological catalysts
10(e) Design rate investigations
- Choose variable and method
- Control confounders
- Measurements and analysis
10(f) Interpret rate data
- Volume/mass/time measurements
- Gradient and plateau
- Measurement limitations
Choose a changing quantityRead slope and final amount separately
- 2026 Pure Chemistry 6092
Official topic 10, pages 20. Original explanations mapped to the stated outcomes; 2026 and 2027 topic content agrees.
- 2027 Pure Chemistry K324
Official topic 10, pages 20. Original explanations mapped to the stated outcomes; 2026 and 2027 topic content agrees.
- 2026 Combined Chemistry 5086 / 5088
Official topic 10, pages 33. Original explanations mapped to the stated outcomes; 2026 and 2027 topic content agrees.
- 2027 Combined Chemistry K326 / K328
Official topic 10, pages 33. Original explanations mapped to the stated outcomes; 2026 and 2027 topic content agrees.