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Rate of Reactions

Full chapter

Rate of Reactions

Explain why reactions speed up, and read what a progress graph actually proves.

O-Level 6092 (2026) / SEC G3 K324 (2027)

01

Explain a rate change using collisions

Changing a condition changes how often particles react.

Reaction rate measures how quickly a reactant is used up or a product forms. Reacting particles must collide, and collisions must have enough energy to lead to reaction. An explanation should connect the changed condition to particle behaviour, then to the number of successful collisions per unit time.

Four factors and their explanations
ChangeParticle explanationImportant control
Higher solution concentrationMore reacting particles per unit volume; more frequent collisionsKeep total solution volume and temperature controlled
Higher gas pressure at fixed temperatureGas particles are closer together; more collisions per unit volume per secondApplies to gaseous reactants, not simply pressing on a solid
Smaller solid pieces, same total massGreater exposed surface area offers more places for collisionsGrinding does not create more total moles of solid
Higher temperatureParticles move faster and collide more energetically; more successful collisionsDo not explain temperature solely as an increase in concentration

A larger lump and equal-mass powder can produce the same final amount of gas while reacting at different speeds. In contrast, adding more of a limiting reactant can change the final amount. Keep the question "how fast?" separate from "how much?".

Check your understandingWhy does powdered calcium carbonate react faster than equal-mass chips in excess acid?Think it through, then reveal the answer
The powder exposes more surface area, so acid particles can collide with more carbonate surface per second. The total amount of carbonate, and hence final carbon dioxide amount, is unchanged.
02

Choose a changing quantity

Match the measurement to the reaction.

Ways to follow progress
MeasurementSuitable situationRate evidence
Gas volume against timeGas-producing reaction; gas can be collectedVolume increase per unit time
Mass against timeA gas escapes from an open reaction vesselMass loss per unit time
Time to a fixed visible endpointA precipitate obscures a mark or a colour reaches a chosen endpointShorter time means a faster average approach to that same endpoint

For a gas syringe, check airtight connections and free plunger movement. For mass loss, prevent splashes so that lost liquid is not mistaken for escaped gas. Start timing consistently. A subjective colour or visibility endpoint is less precise than a clear instrumental measurement, so use the same criterion and repeat.

Worked example

Calculate an average rate

A reaction produces 36 cm3 of gas in its first 40 s.

  1. Average rate = change in gas volume / time interval.
  2. 36/40 = 0.90 cm3 s-1.
  3. This is an average over 40 s; the rate may have fallen throughout that interval.
Answer

0.90 cm3 s-1. State both interval and units.

Check your understandingTwo experiments reach the same endpoint in 20 s and 40 s. Which is faster?Think it through, then reveal the answer
The 20 s experiment. For the same defined amount of change, 1/time can compare relative rates; it does not provide an absolute gas-volume rate unless that volume is known.
03

Read slope and final amount separately

A plateau means product formation has stopped, not that nothing happened.

Same yield, different rates

The faster experiment reaches 44 cubic centimetres earlier; both finish at the same volume.

Illustrative results: equal amounts of magnesium, acid in excess, same temperature; concentration differs.

The gradient of a product-volume graph gives rate. A steeper initial slope means faster initial reaction. The curve becomes less steep as reactants are consumed. A horizontal line means no further gas is collected; a reactant may have been exhausted. A tangent estimates the instantaneous rate at a point; a line joining two measured points gives the average over that interval.

For a mass-loss graph, the mass decreases, so the slope is negative. Use the magnitude of the decrease per time for a positive reaction-rate value. Compare final gas volumes only at the same temperature and pressure. A leak can reduce apparent volume without changing the actual chemical yield.

Worked example

Diagnose a changed curve

A repeat reaches its plateau sooner but at the same final volume. What can be concluded?

  1. It formed the measured product more quickly.
  2. The same final amount formed under the stated gas conditions.
  3. A rate factor such as temperature, concentration or surface area may explain it; the curve alone does not identify which.
Answer

Faster rate, same final amount. Do not claim that a catalyst or temperature change is uniquely proved.

Check your understandingA lower plateau appears after a bung leaks. Does that prove less product formed chemically?Think it through, then reveal the answer
No. Some gas may have escaped collection. Apparatus failure changes the measured amount and must be separated from chemical explanations.
04Pure only

Catalysts provide an easier reaction pathway

They change the rate without being used up overall.

A catalyst increases reaction rate and is chemically unchanged overall at the end. It can take part in intermediate steps before being regenerated. It provides an alternative pathway with lower activation energy, so a larger fraction of collisions can succeed at the same temperature. It does not supply the reaction energy or increase the final yield from a fixed limiting reactant.

Catalyst examples
ContextCatalyst or catalytic material
Haber ammonia synthesisIron
Hydrogenation of unsaturated oilsNickel
Hydrogen peroxide decompositionManganese(IV) oxide
Sulfuric-acid manufactureVanadium(V) oxide, an example of a compound acting as an industrial catalyst
Catalytic convertersMetal catalysts speed conversion of exhaust pollutants
Biological reactionsEnzymes are biological catalysts

On an energy profile, the catalysed route has a lower peak but the same reactant and product levels. Enzymes also increase rates, but their activity depends on conditions; heating them too much can change their structure and reduce activity. Do not treat every catalyst as able to work under any conditions.

Check your understandingAdding a catalyst gives more gas after 20 s. Must it give more gas after the reaction is complete?Think it through, then reveal the answer
No. It can form the same final amount sooner. Final yield is limited by reactant amounts and the reaction, not simply by how quickly it proceeds.
05Pure only

Plan a fair rate investigation

A plan must say how the measurements will support a conclusion.

Investigate acid concentration
  1. Independent variable

    Prepare a range of acid concentrations by measured dilution, keeping total solution volume equal.

  2. Controls

    Use equal magnesium masses and exposed areas, the same initial temperature and the same apparatus.

  3. Measurements

    Record hydrogen volume at fixed times after mixing; repeat each concentration.

  4. Analysis

    Plot volume-time curves and compare initial gradients, with units. A repeat checks reproducibility.

  5. Practical precautions

    Keep away from ignition sources because hydrogen is flammable; use suitable eye protection and avoid a sealed vessel without a free gas outlet.

To investigate particle size instead, vary chip/powder size while holding carbonate mass and acid concentration/volume constant. Use acid in excess if you want final gas amount fixed by carbonate. A suitable method controls the variables that could give the same observed effect, not just the easiest variables to measure.

Check your understandingA student compares hot powdered carbonate with cold chips. Can the difference be attributed to temperature?Think it through, then reveal the answer
No. Both temperature and surface area changed. Use the same particle size when changing temperature, or the same temperature when changing particle size.

Quick revision

Revisit the essentials, then return to an explanation when you need it.

Rate describes change per unit time. Concentration, pressure, temperature and exposed surface area affect successful collisions. On a progress graph, slope indicates rate and the final level indicates measured amount.

Pure only

Pure: a catalyst lowers the activation barrier and is regenerated. A fair investigation changes one variable, controls alternatives and states how data will be analysed.

Scope and references

Learning outcomes and sources

10. Rate of Reactions (6092 / K324). Use the outcome map to find the explanation for a particular syllabus requirement.

See the learning outcome map
  1. 10(a) Explain rate factors

    • Concentration
    • Gas pressure
    • Particle size/surface area
    • Temperature
    • Collisions between reacting particles

    Explain a rate change using collisions

  2. 10(b) Define catalysts and their effects

    • Rate increase
    • Chemically unchanged overall
    • Enzymes included

    Catalysts provide an easier reaction pathway

  3. 10(c) Explain lower activation energy

    • Alternative pathway
    • More successful collisions

    Catalysts provide an easier reaction pathway

  4. 10(d) Recognise catalyst applications

    • Industrial processes
    • Enzymes as biological catalysts

    Catalysts provide an easier reaction pathway

  5. 10(e) Design rate investigations

    • Choose variable and method
    • Control confounders
    • Measurements and analysis

    Plan a fair rate investigation

  6. 10(f) Interpret rate data

    • Volume/mass/time measurements
    • Gradient and plateau
    • Measurement limitations

    Choose a changing quantityRead slope and final amount separately