Skip to notes
Transition Elements

Topic 5 of 6

Why complexes are coloured

Connect d-orbital orientation to visible-light absorption.

A-Level 9476 (2026-2027)

Octahedral ligands split the five d orbitals

Visible-light absorption can promote an electron across the energy gap.

For an isolated metal ion, the five d orbitals have equal energy: they are degenerate. In an octahedral complex, six ligands approach along the positive and negative x, y and z axes. Their electron pairs repel d-electron density unevenly because the orbitals point in different directions.

Orientation determines the amount of repulsion
OrbitalsShape and orientationOctahedral result
dx2-y2 and dz2The first has four lobes along x and y. The second has two z-axis lobes and a ring around its middle. Both put substantial density towards axial ligands.Greater repulsion; the higher-energy pair.
dxy, dxz and dyzFour lobes between the indicated axes, in the xy, xz or yz plane.Less direct repulsion; the lower-energy set of three.

Octahedral splitting and a d-d transition

The two d orbitals directed towards axial ligands are higher in energy than the three oriented between axes. Absorbing a photon with energy equal to the gap can promote a d electron from the lower to the upper set.

The diagram shows relative energies within an octahedral complex. Splitting is caused by ligand interactions; light then supplies the energy for an electronic transition.

If a suitable lower d level is occupied and a higher one can receive an electron, light of energy equal to the gap can cause a d-d transition. Absorbing selected visible wavelengths leaves the complementary mixture to be transmitted or reflected, giving the observed colour. A blue solution transmits blue light; it does not look blue because it absorbs blue most strongly.

Changing the ligand, metal or oxidation state can change the splitting and the wavelength absorbed. This explains why ligand exchange can change colour while oxidation state remains fixed. You do not need a memorised ranking of ligand field strengths for this syllabus.

Check your understandingWhy is Cu2+ often coloured while Zn2+ compounds are commonly colourless or white?Think it through, then reveal the answer
Cu2+ is d9, allowing a suitable d-d excitation in a ligand field. Zn2+ is d10, so that mechanism is unavailable. This is a d-d explanation, not a rule that every substance containing zinc must be colourless regardless of its other ions.