Topic 2 of 5
Concentration-time graphs and half-life
Recognise constant loss versus a constant fraction lost.
A-Level 9476 (2026-2027)
Zero order loses equal amounts; first order loses equal fractions
Only first-order half-life stays constant as concentration falls.
Zero-order concentration-time graph
Concentration falls in a straight line from 0.20 mol per cubic decimetre to zero over 60 seconds. The constant negative gradient means a constant disappearance rate.
First-order concentration-time graph
Concentration falls from 0.20 to 0.10, 0.050 and 0.025 mol per cubic decimetre at 0, 20, 40 and 60 seconds. The curve becomes less steep, but each halving takes 20 seconds.
The half-life is the time for a reactant concentration to fall to half its value at the start of the interval. For first order, each equal time interval removes the same fraction, so half-life is independent of the starting concentration. Look for several successive halvings on a graph; a single halving interval alone cannot establish first-order behaviour.
Worked example
Use repeated half-lives without an integrated rate equation
A first-order reactant has a half-life of 12.0 min. Starting at 0.160 mol dm-3, find its concentration after 36.0 min and the percentage reacted.
- 36.0/12.0 = 3 half-lives.
- Halve three times: 0.160 → 0.0800 → 0.0400 → 0.0200 mol dm-3.
- Fraction remaining = 1/8; fraction reacted = 7/8.
0.0200 mol dm-3 remains; 87.5% has reacted. The first-order model approaches zero but does not reach it after a finite number of half-lives.
When another reactant is maintained effectively constant, an observed simple decay can describe the dependence on the changing reactant under those conditions. State that constraint before attributing the entire reaction an overall order. Integrated rate equations are not required for this syllabus.