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The Periodic Table

Topic 1 of 3

Atomic and physical trends

Change the explanation when the structure changes.

A-Level 8873, revised syllabus (2026-2027)

Read the electron pattern across and down

A period adds electrons to one main shell; a group repeats an outer pattern.

Period 3: the outer shell fills
ElementOuter configurationGroup
Na3s11
Mg3s22
Al3s2 3p113
Si3s2 3p214
P3s2 3p315
S3s2 3p416
Cl3s2 3p517

From Na to Cl the nuclear charge increases. Added electrons enter the third shell, so the shielding of these outer electrons changes relatively little. Stronger effective attraction generally draws the outer shell closer: atomic radius decreases, while first ionisation energy and electronegativity generally increase.

Explain the two first-ionisation-energy exceptions using orbitals. Al loses a higher-energy 3p electron rather than Mg's 3s electron. S loses a paired 3p electron, with extra electron-electron repulsion, whereas P has three singly occupied 3p orbitals. The resulting dips do not mean the general nuclear-charge trend is wrong.

Group 17: same outer pattern, a different shell
ElementOuter configurationRelative pattern down the group
Cl3s2 3p5Smaller atom; stronger attraction to outer electrons
Br4s2 4p5An additional principal shell
I5s2 5p5Larger atom; more shielding

Down Cl to I, the outer shell is farther from the nucleus and is more shielded. These effects outweigh the increased nuclear charge: atomic radius increases, first ionisation energy decreases and electronegativity decreases. The number of outer electrons stays seven.

For ionic radii, compare species with similar electron arrangements. Na+, Mg2+ and Al3+ each have ten electrons: increasing nuclear charge contracts this isoelectronic series. P3-, S2- and Cl- each have eighteen; their radii also decrease in that order. Crossing from a cation series to an anion series introduces a large jump, so ionic radius does not form one smooth decreasing line across Period 3. Down Cl-, Br-, I-, more occupied shells give larger ions.

Check your understandingPut Na+, Mg2+ and Al3+ in decreasing radius and explain.Think it through, then reveal the answer
Na+ > Mg2+ > Al3+. They all have ten electrons, but the proton numbers are 11, 12 and 13. The larger nuclear charge attracts the same electron population more strongly.

A melting-point trend can change its cause

First classify the structure; then compare the attractions.

Why Period 3 melting points do not form a smooth trend
ElementsStructureExplanation
Na, Mg, AlMetallicMelting requires overcoming metallic attraction. More delocalised electrons and greater positive-ion charge help explain the increase from Na to Mg/Al.
SiGiant covalentMany strong covalent bonds extend through the solid, so its melting point is high.
P, S, ClSimple molecular: P4, S8, Cl2Intermolecular attractions, not the bonds inside the molecules, are overcome. These melt far below silicon.

The molecular comparison uses white phosphorus, P4. S8 has a larger, more easily polarised electron cloud than P4, so sulfur has stronger intermolecular attractions and a higher melting point. Cl2 is much smaller and melts much lower. Other allotropes can have different structures; an element name alone does not specify an allotrope.

Na, Mg and Al conduct electricity through mobile delocalised electrons. Conductivity generally increases from Na to Al: each atom supplies one, two and three valence electrons respectively, giving a greater density of mobile charge carriers. The ions remain in the solid lattice. Silicon's covalent network has far fewer mobile carriers at room temperature, so it is a semiconductor with much lower conductivity than the metals. P4, S8 and Cl2 lack mobile charged particles and are electrical insulators in their pure forms.

Halogen volatility: Cl2 to I2
HalogenAppearance near room conditionsVolatility
ChlorineGreenish-yellow gasHighest of these three
BromineRed-brown liquidIntermediate
IodineDark solid; purple vapour on heatingLowest of these three

Down the group, the molecules have more electrons and more polarisable electron clouds. Instantaneous dipole-induced dipole attractions become stronger, so more energy is needed to separate molecules and volatility decreases. This is an intermolecular explanation; do not use the X-X covalent bond strength to explain boiling.

Check your understandingSulfur atoms have more protons than silicon atoms. Why does sulfur still melt much lower?Think it through, then reveal the answer
Silicon is a continuous covalent network, whereas ordinary sulfur consists of S8 molecules. Sulfur melting overcomes weaker intermolecular forces; comparing proton counts misses the change in structure.