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Chemical Equilibria

Topic 1 of 3

Dynamic equilibrium

Understand what stays constant and how a disturbance is opposed.

A-Level 8873, revised syllabus (2026-2027)

Equilibrium is equal rates, not equal amounts

A closed system can look unchanged while molecules continue reacting.

A reversible reaction can proceed in both directions under suitable conditions. For H2(g) + I2(g) ⇌ 2HI(g), hydrogen and iodine form hydrogen iodide, while hydrogen iodide can decompose. Initially, a mixture containing only H2 and I2 has a forward reaction but no reverse reaction: no HI is present yet.

As products accumulate, the reverse reaction becomes possible and its rate increases. Meanwhile, reactants are used up and the forward rate decreases. At dynamic equilibrium, the forward and reverse rates are equal. In a closed system at constant temperature, each concentration then stays constant because each species is made and removed at the same rate. Both reactions continue.

Two different graph signatures of equilibrium

The forward and reverse rates converge to the same nonzero value. Below, reactant and product concentrations become constant at different values. These are qualitative sketches, not the same vertical quantity.

Equal rates explain constant concentrations. The two equilibrium concentrations do not need to be equal.
Check your understandingA sealed mixture has constant concentrations of 0.80 mol dm-3 reactant and 0.15 mol dm-3 product. Does the unequal ratio rule out equilibrium?Think it through, then reveal the answer
No. Equilibrium requires equal forward and reverse rates, not equal concentrations. If the reversible reactions continue at equal rates under unchanged conditions, these unequal concentrations can be equilibrium values.

Predict the response to a disturbance

Track the imposed change separately from the subsequent reaction.

Le Chatelier's Principle: when a system at equilibrium is disturbed, its equilibrium position changes in a direction that tends to oppose the disturbance. The response partly offsets the imposed change; it does not promise to restore every original concentration.

Apply the principle to ammonia formation: an exothermic forward reaction
ChangeImmediate disturbanceSubsequent net reaction
Add H2 at fixed volume and temperature[H2] rises immediately.Forward reaction consumes some added H2; more NH3 forms.
Remove NH3[NH3] falls immediately.Forward reaction replaces some removed product.
Compress the gas mixture at constant temperatureAll gas concentrations rise; total pressure rises.Forward reaction reduces gas amount: 4 mol gas on the left become 2 mol on the right.
Increase temperatureHeat is supplied.The endothermic reverse direction is favoured; the equilibrium NH3 yield decreases.
Add a catalystBoth reaction directions gain a faster pathway.No change in equilibrium composition at the same temperature; equilibrium is reached faster.

For a pressure question, state how pressure changes. Compression changes the reacting gas concentrations. For H2(g) + I2(g) ⇌ 2HI(g), equal gas amounts occur on each side, so compression produces no equilibrium shift in this ideal-gas treatment. Adding an inert gas at fixed volume does not change the concentrations of the reacting gases, even though total pressure rises. Do not use total pressure alone to infer a shift.

Treat heat as a bookkeeping aid for the temperature response: an exothermic forward reaction releases heat, so heating favours the reverse direction. Heat is not a species to insert into a Kc expression. A temperature increase can make the forward reaction faster while making the equilibrium proportion of product smaller; rate and final composition are different questions.

Worked example

Follow a concentration jump

For A(aq) ⇌ B(aq), a little concentrated A solution is added to an equilibrium mixture, with negligible volume change. Describe [A] and [B] immediately and as equilibrium is re-established.

  1. [A] jumps upwards because A was added. [B] is unchanged at the instant of addition.
  2. The forward rate increases, so net conversion of A to B occurs. [A] falls from its immediate peak; [B] rises.
  3. At the new equilibrium the rates are equal again. Both concentrations can differ from their original values, while their equilibrium ratio is fixed by the same temperature.
Answer

Distinguish the instantaneous physical addition from the later chemical readjustment. Do not sketch both concentrations jumping when only A was added.

Check your understandingAn equilibrium 2SO2(g) + O2(g) ⇌ 2SO3(g) has an exothermic forward reaction. Which two changes increase the equilibrium proportion of SO3?Think it through, then reveal the answer
Cooling favours the exothermic forward direction. Compression favours the side with fewer gas moles: 2 rather than 3. Cooling may nevertheless slow production, so this does not alone establish the best industrial conditions.